Engineering Mechanics of Materials |
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Page 177
... longitudinal coordinate with an origin at A. Compute the maximum shearing stress . and the static angles of twist for both segments of the shaft . 4.27 Refer to Figure H4.25 and construct the torque diagram using a longitudinal ...
... longitudinal coordinate with an origin at A. Compute the maximum shearing stress . and the static angles of twist for both segments of the shaft . 4.27 Refer to Figure H4.25 and construct the torque diagram using a longitudinal ...
Page 226
... longitudinal planes , one of which contains the u principal axes of inertia and the second the v principal axes of inertia for all cross - sectional areas along the beam . Every beam , therefore , has two longitudinal principal planes ...
... longitudinal planes , one of which contains the u principal axes of inertia and the second the v principal axes of inertia for all cross - sectional areas along the beam . Every beam , therefore , has two longitudinal principal planes ...
Page 663
... longitudinal stress σ , is exactly one - half that of the circumferential stress o and that both of these stresses ... longitudinal axis of the cylinder through a 30 ° angle . Solution ( a ) Consider a three - dimensional stress element ...
... longitudinal stress σ , is exactly one - half that of the circumferential stress o and that both of these stresses ... longitudinal axis of the cylinder through a 30 ° angle . Solution ( a ) Consider a three - dimensional stress element ...
Contents
T Shear and Moment at Specified Sections | 24 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column components compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length longitudinal M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a segment shaft shear force shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress condition stress element T₁ tensile tension Tmax torque torsional V₁ vertical yield strength yield stress zero