Engineering Mechanics of Materials |
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Page 141
... material is the value of stress beyond which the material experiences a permanent deformation even after the stress is removed . Thus , if the material is loaded to any level of stress within the elastic limit and the load is then ...
... material is the value of stress beyond which the material experiences a permanent deformation even after the stress is removed . Thus , if the material is loaded to any level of stress within the elastic limit and the load is then ...
Page 680
... material B may be transformed into an equivalent amount of material A by changing the actual width b of material B into an equivalent width be of material A. It is evident from Eq . 14.23b that the relation between the actual and the ...
... material B may be transformed into an equivalent amount of material A by changing the actual width b of material B into an equivalent width be of material A. It is evident from Eq . 14.23b that the relation between the actual and the ...
Page 684
... material A and material B , where v1 = VB . For purposes of discussion , assume that EB < E , so that n is less than unity . It follows from Eq . ( b ) that at the junction ( i.e. , at v1 = VB ) , OB is less than σ . A stress ...
... material A and material B , where v1 = VB . For purposes of discussion , assume that EB < E , so that n is less than unity . It follows from Eq . ( b ) that at the junction ( i.e. , at v1 = VB ) , OB is less than σ . A stress ...
Contents
T Shear and Moment at Specified Sections | 24 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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acting allowable angle of twist applied Assume axes axis beam bending cantilever centroidal circle column components compressive Compute Consider constant construct coordinate cross section curve deflection deformation depicted in Figure Determine developed diameter direction discussed elastic element energy equal equation equilibrium Example expressed factor failure flexural force free-body diagram function given inertia joint length limit load material maximum shear stress method modulus moment moments neutral axis normal stress Note obtained plane plot positive principal stresses Problem properties quantity ratio reactions Refer to Figure relation represents resist respect rotation segment shaft shown in Figure slope Solution Solve static steel strain strength structural subjected Substitution supported surface tensile tension theory tion torque unit yield zero