## Engineering mechanics of materials |

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Page 231

horizontal axis of symmetry (i.e., the u principal centroidal axis of inertia)

becomes the

the

Thus the ...

horizontal axis of symmetry (i.e., the u principal centroidal axis of inertia)

becomes the

**neutral axis**for the section. In this case the fibers of the beam abovethe

**neutral axis**are extended and those below the**neutral axis**are shortened.Thus the ...

Page 246

shaded in Figure 5.13b) about the

represents the first moment about the

an edge of the cross section parallel to its

the ...

shaded in Figure 5.13b) about the

**neutral axis**. Alternatively, this integralrepresents the first moment about the

**neutral axis**of the area contained betweenan edge of the cross section parallel to its

**neutral axis**and the surface at whichthe ...

Page 260

and p = 66.6° Since the plane of the load is counterclockwise from the v principal

axis, the

principal axis of inertia. This

5.18.

and p = 66.6° Since the plane of the load is counterclockwise from the v principal

axis, the

**neutral axis**defined by the angle /? is counterclockwise from the uprincipal axis of inertia. This

**neutral axis**is shown properly oriented in Figure5.18.

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### Contents

Introduction | 1 |

Torsionally Loaded Members in Equilibrium | 14 |

Shear and Bending Moment in Beams | 23 |

Copyright | |

19 other sections not shown

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### Common terms and phrases

absolute maximum shear allowable stress aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending cantilever beam Castigliano's second theorem circular column components compressive Compute constant construct coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter differential elastic curve equal equation equilibrium factor of safety flexural stress free-body diagram function given by Eq Homework Problems k-ft k-in kN-m length longitudinal material maximum shear stress modulus of elasticity Mohr's circle neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal strains principal stresses radius Refer to Figure respect rotation section a-a segment shear center shear force shear strain shown in Figure slope solution Solve static statically indeterminate steel stress element subjected Substitution tension tion torque torsional uniform load vertical yield strength yield stress zero