Engineering Mechanics of Materials |
From inside the book
Results 1-3 of 53
Page 231
... axis of inertia ) becomes the neutral axis for the section . In this case the fibers of the beam above the neutral axis are extended and those below the neutral axis are shortened . Thus the stress distribution over any cross section ...
... axis of inertia ) becomes the neutral axis for the section . In this case the fibers of the beam above the neutral axis are extended and those below the neutral axis are shortened . Thus the stress distribution over any cross section ...
Page 246
... neutral axis of the area contained between an edge of the cross section parallel to its neutral axis and the surface at which the shear stress is to be computed . This quantity is traditionally given the symbol Q. Making these substi ...
... neutral axis of the area contained between an edge of the cross section parallel to its neutral axis and the surface at which the shear stress is to be computed . This quantity is traditionally given the symbol Q. Making these substi ...
Page 260
... axis , the neutral axis defined by the angle ẞ is counterclockwise from the u principal axis of inertia . This neutral axis is shown properly oriented in Figure 5.18 . Fibers in the beam downward and to the right of the neutral axis are ...
... axis , the neutral axis defined by the angle ẞ is counterclockwise from the u principal axis of inertia . This neutral axis is shown properly oriented in Figure 5.18 . Fibers in the beam downward and to the right of the neutral axis are ...
Contents
T Shear and Moment at Specified Sections | 24 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
Copyright | |
14 other sections not shown
Other editions - View all
Common terms and phrases
absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column components compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length longitudinal M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a segment shaft shear force shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress condition stress element T₁ tensile tension Tmax torque torsional V₁ vertical yield strength yield stress zero