Engineering Mechanics of Materials |
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Page 55
... perpendicular to the plane on which it acts and it can be either tensile or compressive . A tensile normal stress is one that tends to pull the material particles away from each other , while a compressive normal stress is one that ...
... perpendicular to the plane on which it acts and it can be either tensile or compressive . A tensile normal stress is one that tends to pull the material particles away from each other , while a compressive normal stress is one that ...
Page 231
... perpendicular to the axis of the beam . Its other two planes , parallel to the axis of the beam , are free of any stresses . Also , since the planes on which σ , act are free of shear stresses , it follows that they , as well as any ...
... perpendicular to the axis of the beam . Its other two planes , parallel to the axis of the beam , are free of any stresses . Also , since the planes on which σ , act are free of shear stresses , it follows that they , as well as any ...
Page 309
... perpendicular to the undeformed beam axis from points on the tangent drawn to the elastic curve . ( Point B also lies on the initial position given by the straight line ABC , since the support at B does not settle . ) The tangential ...
... perpendicular to the undeformed beam axis from points on the tangent drawn to the elastic curve . ( Point B also lies on the initial position given by the straight line ABC , since the support at B does not settle . ) The tangential ...
Contents
T Shear and Moment at Specified Sections | 24 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column components compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a segment shaft shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress condition stress element T₁ tensile tension Tmax torque torsional V₁ yield strength yield stress zero σ₁