## Engineering mechanics of materials |

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Page 225

5.14-5.16 Determine the rectangular, principal cen- troidal

the centroidal polar

6, and H5.7. 5.17-5.19 Determine the rectangular, principal centroidal

5.14-5.16 Determine the rectangular, principal cen- troidal

**radii**of gyration andthe centroidal polar

**radius**of gyration for the sections shown in Figures H5.5, H5.6, and H5.7. 5.17-5.19 Determine the rectangular, principal centroidal

**radii**of ...Page 659

Initially, the inside

the inner cylinder, and the jacket is expanded by heating, for easy placement on

the inner cylinder. If the difference between the inside

...

Initially, the inside

**radius**of the jacket is a little smaller than the outside**radius**ofthe inner cylinder, and the jacket is expanded by heating, for easy placement on

the inner cylinder. If the difference between the inside

**radius**of the jacket and the...

Page 660

inside and outside

to represent the outside

jacket because their difference Ar is very small. Assume both jacket and the inner

...

inside and outside

**radii**, respectively, for the jacket. The symbol r2 may be usedto represent the outside

**radius**of the inner cylinder and the inside**radius**of thejacket because their difference Ar is very small. Assume both jacket and the inner

...

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### Contents

Introduction | 1 |

Torsionally Loaded Members in Equilibrium | 14 |

Shear and Bending Moment in Beams | 23 |

Copyright | |

19 other sections not shown

### Other editions - View all

### Common terms and phrases

absolute maximum shear allowable stress aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending cantilever beam Castigliano's second theorem circular column components compressive Compute constant construct coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter differential elastic curve equal equation equilibrium factor of safety flexural stress free-body diagram function given by Eq Homework Problems k-ft k-in kN-m length longitudinal material maximum shear stress modulus of elasticity Mohr's circle neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal strains principal stresses radius Refer to Figure respect rotation section a-a segment shear center shear force shear strain shown in Figure slope solution Solve static statically indeterminate steel stress element subjected Substitution tension tion torque torsional uniform load vertical yield strength yield stress zero