Engineering Mechanics of Materials |
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Page 75
... radius , and hence the one provid- ing the absolute maximum shear stress , is the one in the σ1 - 03 plane for which the 73 radius is ( 01-03 ) / 2 = σ1 / 2 . Thus , once the three principal stresses for a given stress condition are ...
... radius , and hence the one provid- ing the absolute maximum shear stress , is the one in the σ1 - 03 plane for which the 73 radius is ( 01-03 ) / 2 = σ1 / 2 . Thus , once the three principal stresses for a given stress condition are ...
Page 659
... radius of the jacket is a little smaller than the outside radius of the inner cylinder , and the jacket is expanded by heating , for easy placement on the inner cylinder . If the difference between the inside radius of the jacket and ...
... radius of the jacket is a little smaller than the outside radius of the inner cylinder , and the jacket is expanded by heating , for easy placement on the inner cylinder . If the difference between the inside radius of the jacket and ...
Page 660
... radius of the inner cylinder and the inside radius of the jacket because their difference Ar is very small . Assume both jacket and the inner cylinder to be made of the same material . When the shrink - fitting process is completed ...
... radius of the inner cylinder and the inside radius of the jacket because their difference Ar is very small . Assume both jacket and the inner cylinder to be made of the same material . When the shrink - fitting process is completed ...
Contents
T Shear and Moment at Specified Sections | 24 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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Common terms and phrases
absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column components compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length longitudinal M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a segment shaft shear force shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress condition stress element T₁ tensile tension Tmax torque torsional V₁ vertical yield strength yield stress zero