Engineering Mechanics of Materials |
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Page 332
... ratio of the bending to shear deflection at the free end of the cantilever beam varies as the square of the length / depth ratio . This function is plotted in Figure 6.24 ( c ) and reveals that for large ( L / h ) ratios ( e.g. , L / h ...
... ratio of the bending to shear deflection at the free end of the cantilever beam varies as the square of the length / depth ratio . This function is plotted in Figure 6.24 ( c ) and reveals that for large ( L / h ) ratios ( e.g. , L / h ...
Page 334
... ratio . This function is plotted in Figure 6.25 ( c ) and reveals that for large depth / span ratios ( say , L / h > 10 ) , the shear deflection is less than 100 of the bending deflection . At an L / h ratio of unity , the shear ...
... ratio . This function is plotted in Figure 6.25 ( c ) and reveals that for large depth / span ratios ( say , L / h > 10 ) , the shear deflection is less than 100 of the bending deflection . At an L / h ratio of unity , the shear ...
Page 593
... ratio of these torques . Explain why this ratio is independent of the material and geometric properties of the shaft . Of course , the ratio only applies to a solid circular shaft . 12.14 A solid circular shaft fabricated of a material ...
... ratio of these torques . Explain why this ratio is independent of the material and geometric properties of the shaft . Of course , the ratio only applies to a solid circular shaft . 12.14 A solid circular shaft fabricated of a material ...
Contents
T Shear and Moment at Specified Sections | 24 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column components compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length longitudinal M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a segment shaft shear force shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress condition stress element T₁ tensile tension Tmax torque torsional V₁ vertical yield strength yield stress zero