Engineering Mechanics of Materials |
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Page 334
... shear deflection varies as the square of the length / depth ratio . This function is plotted in Figure 6.25 ( c ) ... center C , of the end cross section , which assures that the beam will bend without twisting . In the cross section depicted ...
... shear deflection varies as the square of the length / depth ratio . This function is plotted in Figure 6.25 ( c ) ... center C , of the end cross section , which assures that the beam will bend without twisting . In the cross section depicted ...
Page 672
... shear center of the channel section are established as given by Eqs . ( g ) and ( h ) , and its location is depicted by point C , in Figure 14.8 ( d ) . Note that the shear center of a given cross section is a function only of its ...
... shear center of the channel section are established as given by Eqs . ( g ) and ( h ) , and its location is depicted by point C , in Figure 14.8 ( d ) . Note that the shear center of a given cross section is a function only of its ...
Page 765
... shear stress , 67 , 68 Allowable stress , 489-90 American Institute of Steel Construction , 737-45 American Society ... center of shear . See Shear center concrete . See Reinforced concrete beams curved . See Curved beams defined , 23 ...
... shear stress , 67 , 68 Allowable stress , 489-90 American Institute of Steel Construction , 737-45 American Society ... center of shear . See Shear center concrete . See Reinforced concrete beams curved . See Curved beams defined , 23 ...
Contents
T Shear and Moment at Specified Sections | 24 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column components compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length longitudinal M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a segment shaft shear force shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress condition stress element T₁ tensile tension Tmax torque torsional V₁ vertical yield strength yield stress zero