## Engineering mechanics of materials |

### From inside the book

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Page 24

To determine the internal effects of the applied forces, imagine a cutting plane, A-

A, passed perpendicular to the x ... The force V is termed the

section A- A and the couple M is termed the bending moment at section A- A. The

V ...

To determine the internal effects of the applied forces, imagine a cutting plane, A-

A, passed perpendicular to the x ... The force V is termed the

**shear force**atsection A- A and the couple M is termed the bending moment at section A- A. The

V ...

Page 243

The

distributed in some manner over the cross-sectional area of the beam. In order to

derive an approximate distribution for the shear stresses in symmetrically loaded

...

The

**shear force**V represents the resultant of a system of shear stresses that aredistributed in some manner over the cross-sectional area of the beam. In order to

derive an approximate distribution for the shear stresses in symmetrically loaded

...

Page 245

A normal force Fl representing the resultant of the normal stresses on plane ijkl

produced by the moment Mu . This resultant force is ... A

representing the resultant of the shear stresses xvx acting on surface efij. Since

the shear ...

A normal force Fl representing the resultant of the normal stresses on plane ijkl

produced by the moment Mu . This resultant force is ... A

**shear force**F3representing the resultant of the shear stresses xvx acting on surface efij. Since

the shear ...

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### Contents

Introduction | 1 |

Torsionally Loaded Members in Equilibrium | 14 |

Shear and Bending Moment in Beams | 23 |

Copyright | |

19 other sections not shown

### Other editions - View all

### Common terms and phrases

absolute maximum shear allowable stress aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending cantilever beam Castigliano's second theorem circular column components compressive Compute constant construct coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter differential elastic curve equal equation equilibrium factor of safety flexural stress free-body diagram function given by Eq Homework Problems k-ft k-in kN-m length longitudinal material maximum shear stress modulus of elasticity Mohr's circle neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal strains principal stresses radius Refer to Figure respect rotation section a-a segment shear center shear force shear strain shown in Figure slope solution Solve static statically indeterminate steel stress element subjected Substitution tension tion torque torsional uniform load vertical yield strength yield stress zero