## Engineering mechanics of materials |

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Page 84

strain, y, one for each of the two line elements being considered. If after distortion,

line tt in Figure 2.13(c) rotates to a new position t't' while line nn remains fixed, the

strain, y, one for each of the two line elements being considered. If after distortion,

line tt in Figure 2.13(c) rotates to a new position t't' while line nn remains fixed, the

**shear strain**between line nn and line ff (proceeding from nn to tt in a ccw ...Page 92

It is, therefore, important that one labels the three principal strains properly and in

accordance with the algebraic ... In all three cases, the absolute value of the

maximum

It is, therefore, important that one labels the three principal strains properly and in

accordance with the algebraic ... In all three cases, the absolute value of the

maximum

**shear strain**occurs between two orthogonal axes bisecting the 90° ...Page 98

2.35 The following information is known about the plane strain condition at a

point in a structural member. e2 = -200 x 10 - 6 e3 = - 1200 x 10 "6 Refer to

Figure H2.35 and determine: (a) The maximum

, and y2) ...

2.35 The following information is known about the plane strain condition at a

point in a structural member. e2 = -200 x 10 - 6 e3 = - 1200 x 10 "6 Refer to

Figure H2.35 and determine: (a) The maximum

**shear strain**in the xy plane (i.e., y, and y2) ...

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### Contents

Introduction | 1 |

Torsionally Loaded Members in Equilibrium | 14 |

Shear and Bending Moment in Beams | 23 |

Copyright | |

19 other sections not shown

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### Common terms and phrases

absolute maximum shear allowable stress aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending cantilever beam Castigliano's second theorem circular column components compressive Compute constant construct coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter differential elastic curve equal equation equilibrium factor of safety flexural stress free-body diagram function given by Eq Homework Problems k-ft k-in kN-m length longitudinal material maximum shear stress modulus of elasticity Mohr's circle neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal strains principal stresses radius Refer to Figure respect rotation section a-a segment shear center shear force shear strain shown in Figure slope solution Solve static statically indeterminate steel stress element subjected Substitution tension tion torque torsional uniform load vertical yield strength yield stress zero