Engineering Mechanics of Materials |
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Page 288
B. B. Muvdi, J. W. McNabb. 6.17 A linearly varying loading is applied to the simply supported beam of Figure H6.17 . For an origin at point A , substitute the loading function w ( x ) into Eq . 6.12 and derive equations for shear ...
B. B. Muvdi, J. W. McNabb. 6.17 A linearly varying loading is applied to the simply supported beam of Figure H6.17 . For an origin at point A , substitute the loading function w ( x ) into Eq . 6.12 and derive equations for shear ...
Page 290
... Simply supported beam - uniformly distributed loading v -w [ 3 01 = W x 24Elu 02-01 WX V = ( L3 − 2Lx2 + x3 ) 24Elu + 01 02 L Case 2. Simply supported beam - concentrated load at any point ע V = -5wL4 384Elu Maximum at center 01 ...
... Simply supported beam - uniformly distributed loading v -w [ 3 01 = W x 24Elu 02-01 WX V = ( L3 − 2Lx2 + x3 ) 24Elu + 01 02 L Case 2. Simply supported beam - concentrated load at any point ע V = -5wL4 384Elu Maximum at center 01 ...
Page 595
... simply supported beam loaded by a uniform load as shown in Figure 12.14 ( a ) will resist increasing loads until a plastic hinge forms at the center under the action of the fully plastic load , w ,. A larger force cannot be applied to the ...
... simply supported beam loaded by a uniform load as shown in Figure 12.14 ( a ) will resist increasing loads until a plastic hinge forms at the center under the action of the fully plastic load , w ,. A larger force cannot be applied to the ...
Contents
T Shear and Moment at Specified Sections | 24 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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acting allowable angle of twist applied Assume axes axis beam bending cantilever centroidal circle column components compressive Compute Consider constant construct coordinate cross section curve deflection deformation depicted in Figure Determine developed diameter direction discussed elastic element energy equal equation equilibrium Example expressed factor failure flexural force free-body diagram function given inertia joint length limit load material maximum shear stress method modulus moment moments neutral axis normal stress Note obtained plane plot positive principal stresses Problem properties quantity ratio reactions Refer to Figure relation represents resist respect rotation segment shaft shown in Figure slope Solution Solve static steel strain strength structural subjected Substitution supported surface tensile tension theory tion torque unit yield zero