Engineering Mechanics of Materials |
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Page 560
... steel and is to have an S ( Standard I ) section . Use the information contained in Figure 8.14 ( a ) . 11,22 Refer to Example 11.5 and Figure 11.9 and design members CE and CD . As stated in Example 11.5 , these two members are ...
... steel and is to have an S ( Standard I ) section . Use the information contained in Figure 8.14 ( a ) . 11,22 Refer to Example 11.5 and Figure 11.9 and design members CE and CD . As stated in Example 11.5 , these two members are ...
Page 688
... steel rods by using Eq . 14.27 modified as follows . For the concrete and steel fibers , F. Oc = F1 and Ас As Substitute these into Eq . 14.27 to give o , L. Ec 6 , L 、= Es Note that L - L1 = L and solve for σ : Es Os = Oc Ec or Os ...
... steel rods by using Eq . 14.27 modified as follows . For the concrete and steel fibers , F. Oc = F1 and Ас As Substitute these into Eq . 14.27 to give o , L. Ec 6 , L 、= Es Note that L - L1 = L and solve for σ : Es Os = Oc Ec or Os ...
Page 693
... steel rods by the yield stress of the steel . Commonly employed reinforce- ment steels have yield stresses of 40 , 50 , and 60 ksi . Since reinforcing bar diameters are usually small compared to beam depths , the stress variation over ...
... steel rods by the yield stress of the steel . Commonly employed reinforce- ment steels have yield stresses of 40 , 50 , and 60 ksi . Since reinforcing bar diameters are usually small compared to beam depths , the stress variation over ...
Contents
T Shear and Moment at Specified Sections | 24 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column components compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length longitudinal M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a segment shaft shear force shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress condition stress element T₁ tensile tension Tmax torque torsional V₁ vertical yield strength yield stress zero