## Engineering mechanics of materials |

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Page 560

Homework Problems 11.21 Refer to Example 11.5 and Figure 11.9 and design

member AC, which is to be made of structural

I) section. Use the information contained in Figure 8.14(a). 11.22 Refer to ...

Homework Problems 11.21 Refer to Example 11.5 and Figure 11.9 and design

member AC, which is to be made of structural

**steel**and is to have an S (StandardI) section. Use the information contained in Figure 8.14(a). 11.22 Refer to ...

Page 688

Once the stress is calculated in the fictional concrete it must be interpreted as a

stress in the

and

a ...

Once the stress is calculated in the fictional concrete it must be interpreted as a

stress in the

**steel**rods by using Eq. 14.27 modified as follows. For the concreteand

**steel**fibers, F F a,-- and as = -± Substitute these into Eq. 14.27 to give acLc =a ...

Page 693

For example, /} = 0.80 for/; = 5000 psi. On the tension side, the resultant ultimate

force is obtained by multiplying the area of the

For example, /} = 0.80 for/; = 5000 psi. On the tension side, the resultant ultimate

force is obtained by multiplying the area of the

**steel**rods by the yield stress of the**steel**. Commonly employed reinforcement**steels**have yield stresses of 40, 50, ...### What people are saying - Write a review

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### Contents

Introduction | 1 |

Torsionally Loaded Members in Equilibrium | 14 |

Shear and Bending Moment in Beams | 23 |

Copyright | |

19 other sections not shown

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### Common terms and phrases

absolute maximum shear allowable stress aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending cantilever beam Castigliano's second theorem circular column components compressive Compute constant construct coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter differential elastic curve equal equation equilibrium factor of safety flexural stress free-body diagram function given by Eq Homework Problems k-ft k-in kN-m length longitudinal material maximum shear stress modulus of elasticity Mohr's circle neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal strains principal stresses radius Refer to Figure respect rotation section a-a segment shear center shear force shear strain shown in Figure slope solution Solve static statically indeterminate steel stress element subjected Substitution tension tion torque torsional uniform load vertical yield strength yield stress zero