Engineering Mechanics of Materials |
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Page 341
... stress system induced in the shaft , at any cross section along its length , is a simple uniform normal stress distribution whose intensity σ , is given by Eq . 3.1 . The member shown in Figure 7.1 ( c ) is subjected to the torque T ...
... stress system induced in the shaft , at any cross section along its length , is a simple uniform normal stress distribution whose intensity σ , is given by Eq . 3.1 . The member shown in Figure 7.1 ( c ) is subjected to the torque T ...
Page 346
... stress distribution is shown for the arbitrary cross section a - a in the lower part of Figure 7.4 ( c ) . Since the stresses shown in Figure 7.4 ( b ) and ( c ) are both normal stresses acting over the same cross section of the member ...
... stress distribution is shown for the arbitrary cross section a - a in the lower part of Figure 7.4 ( c ) . Since the stresses shown in Figure 7.4 ( b ) and ( c ) are both normal stresses acting over the same cross section of the member ...
Page 349
... stress distributions ( i.e. , algebraic addition according to Eq . 7.1 ) yields the composite stress distribution shown in Figure 7.5 ( f ) . Note that the point of zero stress , point O , is a distance of 0.016 m from the upper edge of ...
... stress distributions ( i.e. , algebraic addition according to Eq . 7.1 ) yields the composite stress distribution shown in Figure 7.5 ( f ) . Note that the point of zero stress , point O , is a distance of 0.016 m from the upper edge of ...
Contents
T Shear and Moment at Specified Sections | 24 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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acting allowable angle of twist applied Assume axes axis beam bending cantilever centroidal circle column components compressive Compute Consider constant construct coordinate cross section curve deflection deformation depicted in Figure Determine developed diameter direction discussed elastic element energy equal equation equilibrium Example expressed factor failure flexural force free-body diagram function given inertia joint length limit load material maximum shear stress method modulus moment moments neutral axis normal stress Note obtained plane plot positive principal stresses Problem properties quantity ratio reactions Refer to Figure relation represents resist respect rotation segment shaft shown in Figure slope Solution Solve static steel strain strength structural subjected Substitution supported surface tensile tension theory tion torque unit yield zero