Engineering Mechanics of Materials |
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Page 142
... tension or compression , if the longitudinal strain ( i.e. , the strain in the direction of the applied load ) is & LON , the transverse strain & TR ( i.e. , the strain in any direction perpendicular to the applied load ) is -μELON ...
... tension or compression , if the longitudinal strain ( i.e. , the strain in the direction of the applied load ) is & LON , the transverse strain & TR ( i.e. , the strain in any direction perpendicular to the applied load ) is -μELON ...
Page 369
... tension or compression test . The critical or limiting value to is the maximum shear stress in the tension or compression test when failure by yielding ( inelastic action ) occurs . For a uniaxial stress condition , the shear stress is ...
... tension or compression test . The critical or limiting value to is the maximum shear stress in the tension or compression test when failure by yielding ( inelastic action ) occurs . For a uniaxial stress condition , the shear stress is ...
Page 373
... tension or compression test is given by the expression ( ud ) uniaxial = 1 + μ 0 0 3E ( 7.11 ) which is obtained from Eq . 7.10b by setting σ2 and 3 equal to zero and σ , equal to 00. The quantity expressed in Eq . 7.11 represents a ...
... tension or compression test is given by the expression ( ud ) uniaxial = 1 + μ 0 0 3E ( 7.11 ) which is obtained from Eq . 7.10b by setting σ2 and 3 equal to zero and σ , equal to 00. The quantity expressed in Eq . 7.11 represents a ...
Contents
T Shear and Moment at Specified Sections | 24 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column components compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length longitudinal M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a segment shaft shear force shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress condition stress element T₁ tensile tension Tmax torque torsional V₁ vertical yield strength yield stress zero