Engineering Mechanics of Materials |
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Page 193
... thickness ratio of this tube is 9.5 , and the corresponding percentage error is 4.91 percent . For larger radius to thickness ratios , the results obtained for Eqs . 4.32 and 4.19 would differ by even smaller percentages . ( b ) Since ...
... thickness ratio of this tube is 9.5 , and the corresponding percentage error is 4.91 percent . For larger radius to thickness ratios , the results obtained for Eqs . 4.32 and 4.19 would differ by even smaller percentages . ( b ) Since ...
Page 650
B. B. Muvdi, J. W. McNabb. thickness of the cylindrical vessel ; if the variation of this stress over the thickness is such that it may be assumed approximately constant , the cylindrical vessel is referred to as thin - walled ; if not ...
B. B. Muvdi, J. W. McNabb. thickness of the cylindrical vessel ; if the variation of this stress over the thickness is such that it may be assumed approximately constant , the cylindrical vessel is referred to as thin - walled ; if not ...
Page 660
... thickness is comparable to that found for the pipe in Example 14.1 . The inner cylinder is subjected to the external pressure p ; only , and therefore the circumferential stress distribution across its wall thickness is similar to that ...
... thickness is comparable to that found for the pipe in Example 14.1 . The inner cylinder is subjected to the external pressure p ; only , and therefore the circumferential stress distribution across its wall thickness is similar to that ...
Contents
T Shear and Moment at Specified Sections | 24 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column components compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length longitudinal M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a segment shaft shear force shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress condition stress element T₁ tensile tension Tmax torque torsional V₁ vertical yield strength yield stress zero