Engineering Mechanics of Materials |
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Page 141
... YIELD POINT . The yield point , σ ,, is the stress at which the material continues to deform without further ... STRENGTH . For materials having a stress - strain diagram such as shown in Figure 3.13 ( those that do not exhibit a well - ...
... YIELD POINT . The yield point , σ ,, is the stress at which the material continues to deform without further ... STRENGTH . For materials having a stress - strain diagram such as shown in Figure 3.13 ( those that do not exhibit a well - ...
Page 732
... Yield strength ( 103 psi ) 45 45-50 50 50 55 Tensile strength ( 103 psi ) 60 ° 65-70 65 ° 60 70 ° Cold bending + Elongation in 2 in ( % ) 11 25 1t 22 1t 22 Ot 248 112t 20 82500 75 ° 18 8282 Adding 0 20 % ( minimum ) Cu to HSLA steels ...
... Yield strength ( 103 psi ) 45 45-50 50 50 55 Tensile strength ( 103 psi ) 60 ° 65-70 65 ° 60 70 ° Cold bending + Elongation in 2 in ( % ) 11 25 1t 22 1t 22 Ot 248 112t 20 82500 75 ° 18 8282 Adding 0 20 % ( minimum ) Cu to HSLA steels ...
Page 734
... Yield strength ( 103 psi ) 23 28-44 22-39 21-32 Tensile strength ( 103 psi ) 34 38-53 34-50 33-42 Impact strength , Charpy ( ft - lb ) 20 3.2 3.2 Fatigue endurance limit ( 103 psi ) 14 16-23 15-18 16-24 Creep strength , 0.1 % in 100 hr ...
... Yield strength ( 103 psi ) 23 28-44 22-39 21-32 Tensile strength ( 103 psi ) 34 38-53 34-50 33-42 Impact strength , Charpy ( ft - lb ) 20 3.2 3.2 Fatigue endurance limit ( 103 psi ) 14 16-23 15-18 16-24 Creep strength , 0.1 % in 100 hr ...
Contents
T Shear and Moment at Specified Sections | 24 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column components compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length longitudinal M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a segment shaft shear force shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress condition stress element T₁ tensile tension Tmax torque torsional V₁ vertical yield strength yield stress zero