Introduction to Mechanics of Deformable Solids |
From inside the book
Results 1-3 of 69
Page 55
Therefore , at each stage in the twisting deformation the circle remains a circle
with the central angle between any two points unchanged . Axial symmetry does
not rule out a change in radius or an axial displacement , nor does it restrict the ...
Therefore , at each stage in the twisting deformation the circle remains a circle
with the central angle between any two points unchanged . Axial symmetry does
not rule out a change in radius or an axial displacement , nor does it restrict the ...
Page 171
If zero shear strain is to correspond to the zero shear stress at the corners of the
square , the right angle between the edge parallel to the axis of the shaft and
each of the perpendicular lines on the faces prior to twisting must remain a right ...
If zero shear strain is to correspond to the zero shear stress at the corners of the
square , the right angle between the edge parallel to the axis of the shaft and
each of the perpendicular lines on the faces prior to twisting must remain a right ...
Page 228
This plane makes an angle of 30° counterclockwise with the plane on which the
10 , 000 - psi stress acts . Therefore the corresponding point on the circle is on
the radial line from the center which makes an angle of twice 30° , or 60° ...
This plane makes an angle of 30° counterclockwise with the plane on which the
10 , 000 - psi stress acts . Therefore the corresponding point on the circle is on
the radial line from the center which makes an angle of twice 30° , or 60° ...
What people are saying - Write a review
We haven't found any reviews in the usual places.
Other editions - View all
Common terms and phrases
acts actual addition angle answer applied assemblage axial axis beam behavior bending carry circle circular column combined compatibility components compression compressive stress Consider constant creep cross section curve deflection deformation determined diameter dimensions direction displacement effect elastic equal equation example Figure Find force given gives homogeneous idealization increase independent initial interior isotropic length limit linear linear-elastic load material maximum Maxwell modulus moment needed nonlinear normal obtained outer plane plastic positive pressure principal Prob problem produced pure radius range ratio relation replaced requires response result rotation shear stress shell shown shows simple sketch solution steel strain stress-strain relations structural Suppose surface symmetry temperature tensile tension thickness thin-walled tube twisting uniform unloading versus viscous yield zero