## Introduction to Mechanics of Deformable Solids |

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Page 72

Of course , the stresses computed from the dead weights alone are not the actual

stresses . A normal

the material . As seen in Fig . 5 . 1 , the standard tension test then starts out as ...

Of course , the stresses computed from the dead weights alone are not the actual

stresses . A normal

**compressive stress**po must be added on every plane throughthe material . As seen in Fig . 5 . 1 , the standard tension test then starts out as ...

Page 233

16 Plane stress - zero cannot be ignored . 01 - 03 ( a ) Tmax = ' 1 = " > or ( 6 ) ...

Heavy dashed lines replace the heavy full lines of ( a ) to ( d ) to emphasize that

now the maximum

are ...

16 Plane stress - zero cannot be ignored . 01 - 03 ( a ) Tmax = ' 1 = " > or ( 6 ) ...

Heavy dashed lines replace the heavy full lines of ( a ) to ( d ) to emphasize that

now the maximum

**compressive stress**is sought . When either 0 ; or oy or bothare ...

Page 414

A small bending moment M is added to a bar element of length Ax , while the

axial compression P is maintained constant . At each point where the bending

action adds ( Aer | to the compressive strain ea , the normal

on the ...

A small bending moment M is added to a bar element of length Ax , while the

axial compression P is maintained constant . At each point where the bending

action adds ( Aer | to the compressive strain ea , the normal

**compressive stress**on the ...

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acts actual addition angle answer applied assemblage axial axis beam behavior bending carry circle circular column combined compatibility components compression compressive stress Consider constant creep cross section curve deflection deformation determined diameter dimensions direction displacement effect elastic equal equation example Figure Find force given gives homogeneous idealization increase independent initial interior isotropic length limit linear linear-elastic load material maximum Maxwell modulus moment needed nonlinear normal obtained outer plane plastic positive pressure principal Prob problem produced pure radius range ratio relation replaced requires response result rotation shear stress shell shown shows simple sketch solution steel strain stress-strain relations structural Suppose surface symmetry temperature tensile tension thickness thin-walled tube twisting uniform unloading versus viscous yield zero