## Introduction to Mechanics of Deformable Solids |

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Page 72

1 Addition of hydrostatic pressure . recoverable changes , an

due to

course , the stresses computed from the dead weights alone are not the actual ...

1 Addition of hydrostatic pressure . recoverable changes , an

**increase**in volumedue to

**increase**in tension and a decrease due to**increase**in compression . Ofcourse , the stresses computed from the dead weights alone are not the actual ...

Page 140

P1 = P2 = - 004 Pz = + 10oA As the force in bar 4 cannot

further

magnitudes of the forces P1 , P2 , and Pz . The algebraic sum of the forces must

remain ...

P1 = P2 = - 004 Pz = + 10oA As the force in bar 4 cannot

**increase**beyond o A ,further

**increase**in moment M must be carried solely by**increases**in themagnitudes of the forces P1 , P2 , and Pz . The algebraic sum of the forces must

remain ...

Page 417

Instead , the load is

must be examined , not just stability of existing configuration . Figure 16 . 6d

exhibits a combination of moment M and an accompanying minimum

...

Instead , the load is

**increased**continually until failure is reached . Stability of pathmust be examined , not just stability of existing configuration . Figure 16 . 6d

exhibits a combination of moment M and an accompanying minimum

**increase**in...

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acts actual addition angle answer applied assemblage axial axis beam behavior bending carry circle circular column combined compatibility components compression compressive stress Consider constant creep cross section curve deflection deformation determined diameter dimensions direction displacement effect elastic equal equation example Figure Find force given gives homogeneous idealization increase independent initial interior isotropic length limit linear linear-elastic load material maximum Maxwell modulus moment needed nonlinear normal obtained outer plane plastic positive pressure principal Prob problem produced pure radius range ratio relation replaced requires response result rotation shear stress shell shown shows simple sketch solution steel strain stress-strain relations structural Suppose surface symmetry temperature tensile tension thickness thin-walled tube twisting uniform unloading versus viscous yield zero