## Introduction to Mechanics of Deformable Solids |

### From inside the book

Results 1-3 of 43

Page 24

variations and of stress concentrations on the number of cycles

fatigue failure . The word “ failure ” need not connote fracture . A bar which

buckles in compression may do as much damage as one which fractures in

tension .

variations and of stress concentrations on the number of cycles

**needed**forfatigue failure . The word “ failure ” need not connote fracture . A bar which

buckles in compression may do as much damage as one which fractures in

tension .

Page 197

3 : 20 , 21 ) and are

displacements u and w by their time rates of change or velocities du / dt and dw /

dt , strains e by strain rates de / dt , elastic constants E and v by viscous

coefficients ...

3 : 20 , 21 ) and are

**needed**in the stress - strain relation ( 9 . 3 : 22 ) . Replacedisplacements u and w by their time rates of change or velocities du / dt and dw /

dt , strains e by strain rates de / dt , elastic constants E and v by viscous

coefficients ...

Page 292

1 : 8 ) One more condition or piece of information is

stress - strain relations . Knowledge of p will do . Alternatively , as in Sec . 9 . 3 ,

the volume between the tubes , 7 ( 62 – a ) L , may be kept constant (

incompressible ...

1 : 8 ) One more condition or piece of information is

**needed**in addition to thestress - strain relations . Knowledge of p will do . Alternatively , as in Sec . 9 . 3 ,

the volume between the tubes , 7 ( 62 – a ) L , may be kept constant (

incompressible ...

### What people are saying - Write a review

We haven't found any reviews in the usual places.

### Other editions - View all

### Common terms and phrases

acts actual addition angle answer applied assemblage axial axis beam behavior bending carry circle circular column combined compatibility components compression compressive stress Consider constant creep cross section curve deflection deformation determined diameter dimensions direction displacement effect elastic equal equation example Figure Find force given gives homogeneous idealization increase independent initial interior isotropic length limit linear linear-elastic load material maximum Maxwell modulus moment needed nonlinear normal obtained outer plane plastic positive pressure principal Prob problem produced pure radius range ratio relation replaced requires response result rotation shear stress shell shown shows simple sketch solution steel strain stress-strain relations structural Suppose surface symmetry temperature tensile tension thickness thin-walled tube twisting uniform unloading versus viscous yield zero