Introduction to Mechanics of Deformable Solids |
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Page 55
Axial symmetry does not rule out a change in radius or an axial displacement ,
nor does it restrict the angular rotation . ... Instead , one circle in one cross section
of the tube can be taken as reference and the angular rotations of all the other ...
Axial symmetry does not rule out a change in radius or an axial displacement ,
nor does it restrict the angular rotation . ... Instead , one circle in one cross section
of the tube can be taken as reference and the angular rotations of all the other ...
Page 116
A rotation 00 , twice the rotation Oy , 00 = 209 = 40 L = Eh is required for the
middle pair to reach yield , because the strain in these bars is only half the strain
in the outer bars . The lever arm of the resisting moment , correspondingly , is half
as ...
A rotation 00 , twice the rotation Oy , 00 = 209 = 40 L = Eh is required for the
middle pair to reach yield , because the strain in these bars is only half the strain
in the outer bars . The lever arm of the resisting moment , correspondingly , is half
as ...
Page 142
Rotation in time t , due to M applied abruptly and held constant for time ti 3 .
Rotation in time ti due to M applied as a quadratic in time , M = M . ( t / tı ) 2 4 .
Residual stress in each bar produced by the application and removal of M . D .
Assume a ...
Rotation in time t , due to M applied abruptly and held constant for time ti 3 .
Rotation in time ti due to M applied as a quadratic in time , M = M . ( t / tı ) 2 4 .
Residual stress in each bar produced by the application and removal of M . D .
Assume a ...
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acts actual addition angle answer applied assemblage axial axis beam behavior bending carry circle circular column combined compatibility components compression compressive stress Consider constant creep cross section curve deflection deformation determined diameter dimensions direction displacement effect elastic equal equation example Figure Find force given gives homogeneous idealization increase independent initial interior isotropic length limit linear linear-elastic load material maximum Maxwell modulus moment needed nonlinear normal obtained outer plane plastic positive pressure principal Prob problem produced pure radius range ratio relation replaced requires response result rotation shear stress shell shown shows simple sketch solution steel strain stress-strain relations structural Suppose surface symmetry temperature tensile tension thickness thin-walled tube twisting uniform unloading versus viscous yield zero