## Introduction to Mechanics of Deformable Solids |

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Page 168

If uniformity along the entire length of the

distribution of stress on the end cross sections which will keep the end cross

sections plane as well . ( Of course , this is precisely the distribution of stress

enforced ...

If uniformity along the entire length of the

**shaft**is possible , there must be somedistribution of stress on the end cross sections which will keep the end cross

sections plane as well . ( Of course , this is precisely the distribution of stress

enforced ...

Page 170

Examine the homogeneous square

tubes provide no guide to the solution , because only a circular solid or hollow

Examine the homogeneous square

**shaft**first ( Fig . 8 . 10 ) . Concentric circulartubes provide no guide to the solution , because only a circular solid or hollow

**shaft**can result from their combination . It is easy to see that no reliance can be ...Page 171

Rotation of 90° about the axis of the

end - for - end rotation about A - A ' . If zero shear strain is to correspond to the

zero shear stress at the corners of the square , the right angle between the edge

...

Rotation of 90° about the axis of the

**shaft**leaves the picture unchanged , as doesend - for - end rotation about A - A ' . If zero shear strain is to correspond to the

zero shear stress at the corners of the square , the right angle between the edge

...

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acts actual addition angle answer applied assemblage axial axis beam behavior bending carry circle circular column combined compatibility components compression compressive stress Consider constant creep cross section curve deflection deformation determined diameter dimensions direction displacement effect elastic equal equation example Figure Find force given gives homogeneous idealization increase independent initial interior isotropic length limit linear linear-elastic load material maximum Maxwell modulus moment needed nonlinear normal obtained outer plane plastic positive pressure principal Prob problem produced pure radius range ratio relation replaced requires response result rotation shear stress shell shown shows simple sketch solution steel strain stress-strain relations structural Suppose surface symmetry temperature tensile tension thickness thin-walled tube twisting uniform unloading versus viscous yield zero