Electrodynamics of Continuous MediaCovers the theory of electromagnetic fields in matter, and the theory of the macroscopic electric and magnetic properties of matter. There is a considerable amount of new material particularly on the theory of the magnetic properties of matter and the theory of optical phenomena with new chapters on spatial dispersion and non-linear optics. The chapters on ferromagnetism and antiferromagnetism and on magnetohydrodynamics have been substantially enlarged and eight other chapters have additional sections. |
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Page 11
... perpendicular to the vector ro and distant ro – a' = R*/(a + ro) = R*/2a from the origin. (3) The method of conformal mapping. A field which depends on only two Cartesian coordinates (x and y, say) is said to be two-dimensional. The ...
... perpendicular to the vector ro and distant ro – a' = R*/(a + ro) = R*/2a from the origin. (3) The method of conformal mapping. A field which depends on only two Cartesian coordinates (x and y, say) is said to be two-dimensional. The ...
Page 12
... perpendicular to the plane), it follows that e = (1/4t)AA, (3.17) where AA is the change in A on passing counterclockwise round the closed equipotential line. The simplest example of the complex potential is that of the field of a ...
... perpendicular to the plane), it follows that e = (1/4t)AA, (3.17) where AA is the change in A on passing counterclockwise round the closed equipotential line. The simplest example of the complex potential is that of the field of a ...
Page 14
... perpendicular to the axis of the cylinder. The solution of the two-dimensional Laplace's equation which depends only on a constant vector is 41 = constant x & grad(log r) = constant x & r/r”. Adding po = - © r and putting the constant ...
... perpendicular to the axis of the cylinder. The solution of the two-dimensional Laplace's equation which depends only on a constant vector is 41 = constant x & grad(log r) = constant x & r/r”. Adding po = - © r and putting the constant ...
Page 15
... perpendicular to the surface of the conductor, and passing through the dipole; let the dipole moment vector 4° lie in the xy-plane. The image of the dipole is at the point – x and has a moment 2", = 2, 3", = – 9,. The required energy of ...
... perpendicular to the surface of the conductor, and passing through the dipole; let the dipole moment vector 4° lie in the xy-plane. The image of the dipole is at the point – x and has a moment 2", = 2, 3", = – 9,. The required energy of ...
Page 17
... half-plane shown by the dashed line in Fig. 6, which is perpendicular to the radius AO of the cap and passes through the point B on its rim. A. FIG. 6 The angle y = t –6, where §3 Methods of solving problems in electrostatics 17.
... half-plane shown by the dashed line in Fig. 6, which is perpendicular to the radius AO of the cap and passes through the point B on its rim. A. FIG. 6 The angle y = t –6, where §3 Methods of solving problems in electrostatics 17.
Contents
1 | |
34 | |
CHAPTER III STEADY CURRENT | 86 |
CHAPTER IV STATIC MAGNETIC FIELD | 105 |
CHAPTER V FERROMAGNETISM AND ANTIFERROMAGNETISM | 130 |
CHAPTER VI SUPERCONDUCTIVITY | 180 |
CHAPTER VII QUASISTATIC ELECTROMAGNETIC FIELD | 199 |
CHAPTER VIII MAGNETOHYDRODYNAMICS | 225 |
CHAPTER XI ELECTROMAGNETIC WAVES IN ANISOTROPIC MEDIA | 331 |
CHAPTER XII SPATIAL DISPERSION | 358 |
CHAPTER XIII NONLINEAR OPTICS | 372 |
CHAPTER XIV THE PASSAGE OF FAST PARTICLES THROUGH MATTER | 394 |
CHAPTER XV SCATTERING OF ELECTROMAGNETIC WAVES | 413 |
CHAPTER XVI DIFFRACTION OF XRAYS IN CRYSTALS | 439 |
CURVILINEAR COORDINATES | 452 |
INDEX | 455 |
CHAPTER IX THE ELECTROMAGNETIC WAVE EQUATIONS | 257 |
CHAPTER X THE PROPAGATION OF ELECTROMAGNETIC WAVES | 290 |
Other editions - View all
Electrodynamics of Continuous Media: Volume 8 L D Landau,E.M. Lifshitz,L. P. Pitaevskii Snippet view - 1995 |
Common terms and phrases
According angle anisotropy assumed averaging axes axis becomes body boundary conditions calculation called charge coefficient compared components condition conducting conductor consider constant continuous coordinates corresponding crystal curl denote density depends derivative determined dielectric direction discontinuity distance distribution effect electric field ellipsoid energy equal equation expression external factor ferromagnet fluid flux follows force formula frequency function given gives grad Hence incident increases independent induction integral linear magnetic field mean medium neglected normal obtain occur parallel particle particular permittivity perpendicular phase plane polarization positive potential present PROBLEM propagated properties quantities range regarded region relation respect result rotation satisfied scattering simply solution sphere Substituting surface symmetry taken temperature tensor theory thermodynamic transition uniform unit values variable vector volume wave write zero