## Strength of materials |

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Page 97

Such inclined loads cause combined axial and

discussed in Art. 9-2. Sign of

moment is positive if it produces

4-7.

Such inclined loads cause combined axial and

**bending**effects which arediscussed in Art. 9-2. Sign of

**Bending**Moment To many engineers,**bending**moment is positive if it produces

**bending**of the beam concave upward, as in Fig.4-7.

Page 114

As a preliminary to computing the

the shear diagram marked A\,A2,A}, and A4. Ax = J(3X-6) = -9 kN-m A2 = i(7X14)

= +49 kN-m A} = i(2X-4) = -4 kN • m A4 = 3(-12) = -36 kN-m According to Eq. (4-4)

...

As a preliminary to computing the

**bending**moments, we determine the areas ofthe shear diagram marked A\,A2,A}, and A4. Ax = J(3X-6) = -9 kN-m A2 = i(7X14)

= +49 kN-m A} = i(2X-4) = -4 kN • m A4 = 3(-12) = -36 kN-m According to Eq. (4-4)

...

Page 474

We conclude that the flexure | formula may be applied only if the

act in a longitudinal plane parallel to or containing one of the principal axes of the

section. These planes are called the principal planes of

We conclude that the flexure | formula may be applied only if the

**bending**loadsact in a longitudinal plane parallel to or containing one of the principal axes of the

section. These planes are called the principal planes of

**bending**. We are now ...### What people are saying - Write a review

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### Common terms and phrases

allowable stresses aluminum angle area-moment assumed axes axial load beam in Fig beam loaded beam shown bending bolts cantilever beam caused centroid column components compressive stress Compute the maximum concentrated load connector cross section deformations Determine the maximum diameter elastic curve element end moments equal equivalent Euler's formula factor of safety fibers Figure flange flexure formula free-body diagram Hence Hooke's law horizontal Illustrative Problem kips lb/ft length loaded as shown main plate maximum shearing stress maximum stress method midspan deflection Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius reaction rectangular resisting resultant rivet rotation segment shaft shear center shear diagram shearing force shown in Fig slope Solution span static steel strain tensile stress thickness three-moment equation torque torsional U.S. Customary Units uniformly distributed load vertical shear weld zero