## Strength of materials |

### From inside the book

Results 1-3 of 34

Page 76

However, initially there is a 6° mismatch in the location of the

shown in the figure. Determine the maximum shearing stress in each shaft after

the shafts are bolted together. Use G = 12 X 106 psi and neglect deformations of

the ...

However, initially there is a 6° mismatch in the location of the

**bolt**holes, asshown in the figure. Determine the maximum shearing stress in each shaft after

the shafts are bolted together. Use G = 12 X 106 psi and neglect deformations of

the ...

Page 77

Figure 3-6 Flanged

rows of

and subscript 2 refer to

coupling ...

Figure 3-6 Flanged

**bolt**coupling. Occasionally a coupling has two concentricrows of

**bolts**, as in Fig. 3-7. Letting the subscript 1 refer to**bolts**on the outer circleand subscript 2 refer to

**bolts**on the inner circle, the torque capacity of thecoupling ...

Page 78

If the

made of the same material, Gi = G2, the relation between Pt and P2 reduces to ^

= ^ (3-6) This is the case shown in Fig. 3-7. Using the relation between P, and P2,

...

If the

**bolts**on the two circles have the same area, A\ = A2, and if the**bolts**aremade of the same material, Gi = G2, the relation between Pt and P2 reduces to ^

= ^ (3-6) This is the case shown in Fig. 3-7. Using the relation between P, and P2,

...

### What people are saying - Write a review

We haven't found any reviews in the usual places.

### Common terms and phrases

allowable stresses aluminum angle area-moment assumed axes axial load beam in Fig beam loaded beam shown bending bolts cantilever beam caused centroid column components compressive stress Compute the maximum concentrated load connector cross section deformations Determine the maximum diameter elastic curve element end moments equal equivalent Euler's formula factor of safety fibers Figure flange flexure formula free-body diagram Hence Hooke's law horizontal Illustrative Problem kips lb/ft length loaded as shown main plate maximum shearing stress maximum stress method midspan deflection Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius reaction rectangular resisting resultant rivet rotation segment shaft shear center shear diagram shearing force shown in Fig slope Solution span static steel strain tensile stress thickness three-moment equation torque torsional U.S. Customary Units uniformly distributed load vertical shear weld zero