## Strength of materials |

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Page 113

P= 8 kN wa = 2 kN/m distributed load is equal to the area of the load diagram in

this interval; that is, AK = -2 X 3 = -6 kN. ... The

causes the shear at B to increase abruptly by 20 kN to a net positive shear

ordinate ...

P= 8 kN wa = 2 kN/m distributed load is equal to the area of the load diagram in

this interval; that is, AK = -2 X 3 = -6 kN. ... The

**concentrated load**reaction at Bcauses the shear at B to increase abruptly by 20 kN to a net positive shear

ordinate ...

Page 265

A restrained beam 6 m long supports a

the left end and another

Select the lightest wide-flange beam that will support these loads without

exceeding ...

A restrained beam 6 m long supports a

**concentrated load**of 30 kN at 2 m fromthe left end and another

**concentrated load**of 50 kN at 1.5 m from the right end.Select the lightest wide-flange beam that will support these loads without

exceeding ...

Page 280

82 1 if the

intensity hs0 over the middle span. w0L2 1 +20 4u A/2 4->l+«Xl+fl-l h-qL2 1 + 2a

4 *4(1 + aXl + 0) - 1 823. A continuous beam simply supported over three 10-ft

spans ...

82 1 if the

**concentrated load**is replaced by a uniformly distributed load ofintensity hs0 over the middle span. w0L2 1 +20 4u A/2 4->l+«Xl+fl-l h-qL2 1 + 2a

4 *4(1 + aXl + 0) - 1 823. A continuous beam simply supported over three 10-ft

spans ...

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### Common terms and phrases

allowable stresses aluminum angle area-moment assumed axes axial load beam in Fig beam loaded beam shown bending bolts cantilever beam caused centroid column components compressive stress Compute the maximum concentrated load connector cross section deformations Determine the maximum diameter elastic curve element end moments equal equivalent Euler's formula factor of safety fibers Figure flange flexure formula free-body diagram Hence Hooke's law horizontal Illustrative Problem kips lb/ft length loaded as shown main plate maximum shearing stress maximum stress method midspan deflection Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius reaction rectangular resisting resultant rivet rotation segment shaft shear center shear diagram shearing force shown in Fig slope Solution span static steel strain tensile stress thickness three-moment equation torque torsional U.S. Customary Units uniformly distributed load vertical shear weld zero