Strength of MaterialsSimple stress, simple strai, torsion, shear and moment in beams, beam deflections, continuous beams, combined stresses. |
From inside the book
Results 1-3 of 65
Page 320
... element in Fig . 9-9b is subjected only to a normal stress , but the element in Fig . 9-9c is subjected to both normal and shearing stress caused by the N and T components of the equilibrant E. Thus at the same position in a stressed ...
... element in Fig . 9-9b is subjected only to a normal stress , but the element in Fig . 9-9c is subjected to both normal and shearing stress caused by the N and T components of the equilibrant E. Thus at the same position in a stressed ...
Page 321
... element on which the maximum normal stress exists , and its magnitude ; also the orientation of the element on which maximum shearing stress exists , and its magnitude . In general , it is not possible to compute directly the stresses ...
... element on which the maximum normal stress exists , and its magnitude ; also the orientation of the element on which maximum shearing stress exists , and its magnitude . In general , it is not possible to compute directly the stresses ...
Page 323
... element may be subject to the normal stress σ , as well as to shearing stresses 7zx and Tzy . These shearing ... element enclosing the point . As seen in Art . 9-4 , the stresses change with the inclination of the planes passing through ...
... element may be subject to the normal stress σ , as well as to shearing stresses 7zx and Tzy . These shearing ... element enclosing the point . As seen in Art . 9-4 , the stresses change with the inclination of the planes passing through ...
Common terms and phrases
allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bending moment bolts cantilever beam centroid column compressive stress Compute the maximum concentrated load connector cross section deformations Determine the maximum diameter elastic curve element equal equivalent Euler's formula fibers flange flexural stress flexure formula free-body diagram Hence Hooke's law horizontal Illustrative Problem kips kN·m kN/m lb.ft lb/ft length loaded as shown M₁ M₂ maximum shearing stress maximum stress method midspan mm² Mohr's circle moment of inertia neutral axis obtain P₁ plane product of inertia proportional limit R₂ R2 Figure radius reaction resisting resultant rivet segment shaft shear center shear diagram shearing force shown in Fig slope Solution span steel strain tensile stress thickness torque torsional U.S. Customary Units uniformly distributed load vertical shear weld zero ΕΙ