## Strength of materials |

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Page 118

Similarly, the area of the shear diagram between G and D

= 68.4 lb • ft. Since this is a positive increase in bending moment, the moment at

G must be smaller by this amount than the moment at D, or Sketching the bent ...

Similarly, the area of the shear diagram between G and D

**equals**$ X 120 X 1.14= 68.4 lb • ft. Since this is a positive increase in bending moment, the moment at

G must be smaller by this amount than the moment at D, or Sketching the bent ...

Page 159

a-b to those at c-d, the total compressive force Ci over the area abcd (

area abcd multiplied by the average of the stresses aa and ad) can be balanced

only by a shear resistance developed at the horizontal layer dce. Such shear ...

a-b to those at c-d, the total compressive force Ci over the area abcd (

**equal**to thearea abcd multiplied by the average of the stresses aa and ad) can be balanced

only by a shear resistance developed at the horizontal layer dce. Such shear ...

Page 255

Solution: Because of symmetry, the end shears are

are unknown. The simplest condition that determines the unknown end moment ...

Solution: Because of symmetry, the end shears are

**equal**to each other, and each**equals**one-half the applied loads. The end moments also**equal**each other, butare unknown. The simplest condition that determines the unknown end moment ...

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allowable stresses aluminum angle area-moment assumed axes axial load beam in Fig beam loaded beam shown bending bolts cantilever beam caused centroid column components compressive stress Compute the maximum concentrated load connector cross section deformations Determine the maximum diameter elastic curve element end moments equal equivalent Euler's formula factor of safety fibers Figure flange flexure formula free-body diagram Hence Hooke's law horizontal Illustrative Problem kips lb/ft length loaded as shown main plate maximum shearing stress maximum stress method midspan deflection Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius reaction rectangular resisting resultant rivet rotation segment shaft shear center shear diagram shearing force shown in Fig slope Solution span static steel strain tensile stress thickness three-moment equation torque torsional U.S. Customary Units uniformly distributed load vertical shear weld zero