## Strength of materials |

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Page 463

13-16, which shows the free-body diagrams of portions of the

two adjacent sections. The dashed lines indicate a phantom view of the

cantilever beam from which these sections were cut. When the external vertical

shear acts ...

13-16, which shows the free-body diagrams of portions of the

**flanges**cut out bytwo adjacent sections. The dashed lines indicate a phantom view of the

cantilever beam from which these sections were cut. When the external vertical

shear acts ...

Page 467

13-20, we set a moment summation about O equal to zero and obtain Figure 13-

20 [2 M0 = 0] Ve = Hh (a) The value of the

average shear flow in the

a) ...

13-20, we set a moment summation about O equal to zero and obtain Figure 13-

20 [2 M0 = 0] Ve = Hh (a) The value of the

**flange**force H is the product of theaverage shear flow in the

**flange**multiplied by the length of the**flange**. Using Eq. (a) ...

Page 468

We conclude that the shear center coincides with the centroid of the wide-

section. In general, the shear center is located at the intersection of two axes of

symmetry, if they exist. For an unequal flanged H section with relatively thin ...

We conclude that the shear center coincides with the centroid of the wide-

**flange**section. In general, the shear center is located at the intersection of two axes of

symmetry, if they exist. For an unequal flanged H section with relatively thin ...

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### Common terms and phrases

allowable stresses aluminum angle area-moment assumed axes axial load beam in Fig beam loaded beam shown bending bolts cantilever beam caused centroid column components compressive stress Compute the maximum concentrated load connector cross section deformations Determine the maximum diameter elastic curve element end moments equal equivalent Euler's formula factor of safety fibers Figure flange flexure formula free-body diagram Hence Hooke's law horizontal Illustrative Problem kips lb/ft length loaded as shown main plate maximum shearing stress maximum stress method midspan deflection Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius reaction rectangular resisting resultant rivet rotation segment shaft shear center shear diagram shearing force shown in Fig slope Solution span static steel strain tensile stress thickness three-moment equation torque torsional U.S. Customary Units uniformly distributed load vertical shear weld zero