Strength of MaterialsSimple stress, simple strai, torsion, shear and moment in beams, beam deflections, continuous beams, combined stresses. |
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Page 392
... hinged column of the same length . One other type of column is hinged at one end and built in at the other , as in Fig . 11-6 . For it , the point of inflection can be shown to be nearly 0.7L from the hinged end . Hence substituting an ...
... hinged column of the same length . One other type of column is hinged at one end and built in at the other , as in Fig . 11-6 . For it , the point of inflection can be shown to be nearly 0.7L from the hinged end . Hence substituting an ...
Page 393
... hinged column of the same length . All we need do is apply Eq . ( 11-1 ) multiplied by a factor N , which varies ... hinged columns = Effective length Fixed ends 4 L One end fixed , the other hinged 0.7L Both ends hinged 1 L One end ...
... hinged column of the same length . All we need do is apply Eq . ( 11-1 ) multiplied by a factor N , which varies ... hinged columns = Effective length Fixed ends 4 L One end fixed , the other hinged 0.7L Both ends hinged 1 L One end ...
Page 403
... hinged if its cross section is ( a ) circular with a radius of 2 in . and ( b ) 2.5 in . square . 1114. Determine the maximum length of a W250 × 167 section used as a hinged - end column to support a load of 1600 kN . Use AISC ...
... hinged if its cross section is ( a ) circular with a radius of 2 in . and ( b ) 2.5 in . square . 1114. Determine the maximum length of a W250 × 167 section used as a hinged - end column to support a load of 1600 kN . Use AISC ...
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allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bending moment bolts cantilever beam centroid column compressive stress Compute the maximum concentrated load connector cross section deformations Determine the maximum diameter elastic curve element equal equivalent Euler's formula fibers flange flexural stress flexure formula free-body diagram Hence Hooke's law horizontal Illustrative Problem kips kN·m kN/m lb.ft lb/ft length loaded as shown M₁ M₂ maximum shearing stress maximum stress method midspan mm² Mohr's circle moment of inertia neutral axis obtain P₁ plane product of inertia proportional limit R₂ R2 Figure radius reaction resisting resultant rivet segment shaft shear center shear diagram shearing force shown in Fig slope Solution span steel strain tensile stress thickness torque torsional U.S. Customary Units uniformly distributed load vertical shear weld zero ΕΙ