Strength of MaterialsSimple stress, simple strai, torsion, shear and moment in beams, beam deflections, continuous beams, combined stresses. |
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Page 496
... plastic region than it is within the elastic region . Such a material is said to strain - harden ; it does not permit an increase in strain without an increase in stress . A material for which C is zero is called elastic - perfectly plastic ...
... plastic region than it is within the elastic region . Such a material is said to strain - harden ; it does not permit an increase in strain without an increase in stress . A material for which C is zero is called elastic - perfectly plastic ...
Page 498
... plastic ( d ) Section c - c : fully plastic T h / 2 Figure 14-3 Flexure stress distribution as moment is increased . the yield stress , but the stress distribution is still elastic , as shown in part ( b ) . Applying the flexure formula ...
... plastic ( d ) Section c - c : fully plastic T h / 2 Figure 14-3 Flexure stress distribution as moment is increased . the yield stress , but the stress distribution is still elastic , as shown in part ( b ) . Applying the flexure formula ...
Page 518
... plastic case , the limit torque is TL = TYP ( 14-2 ) For symmetrical beams bent into the plastic range , the bending moment is Gypli M = + 20 ypQ Yi ( 14-3 ) where y , defines the elastic - plastic boundary , I ; is the moment of ...
... plastic case , the limit torque is TL = TYP ( 14-2 ) For symmetrical beams bent into the plastic range , the bending moment is Gypli M = + 20 ypQ Yi ( 14-3 ) where y , defines the elastic - plastic boundary , I ; is the moment of ...
Common terms and phrases
allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bending moment bolts cantilever beam centroid column compressive stress Compute the maximum concentrated load connector cross section deformations Determine the maximum diameter elastic curve element equal equivalent Euler's formula fibers flange flexural stress flexure formula free-body diagram Hence Hooke's law horizontal Illustrative Problem kips kN·m kN/m lb.ft lb/ft length loaded as shown M₁ M₂ maximum shearing stress maximum stress method midspan mm² Mohr's circle moment of inertia neutral axis obtain P₁ plane product of inertia proportional limit R₂ R2 Figure radius reaction resisting resultant rivet segment shaft shear center shear diagram shearing force shown in Fig slope Solution span steel strain tensile stress thickness torque torsional U.S. Customary Units uniformly distributed load vertical shear weld zero ΕΙ