Strength of MaterialsSimple stress, simple strai, torsion, shear and moment in beams, beam deflections, continuous beams, combined stresses. |
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Page 97
... positive if it produces bending of the beam concave upward , as in Fig . 4-7 . We prefer to use an equivalent convention which states that upward acting external forces cause positive bending moments with respect to any section ...
... positive if it produces bending of the beam concave upward , as in Fig . 4-7 . We prefer to use an equivalent convention which states that upward acting external forces cause positive bending moments with respect to any section ...
Page 118
... positive and decrease to zero as we move from A to F , the moment curve has correspondingly positive slopes ( i.e. , directed upward to the right ) that decrease to zero slope at F. Between F and B , the vertical shear is increasingly ...
... positive and decrease to zero as we move from A to F , the moment curve has correspondingly positive slopes ( i.e. , directed upward to the right ) that decrease to zero slope at F. Between F and B , the vertical shear is increasingly ...
Page 197
... Positive and negative deviations are shown in Fig . 6-10 . Conversely , a computed positive value for deviation means that the point must lie above the reference tangent . A A B / A B tB / A ( a ) Positive deviation ; B located above ...
... Positive and negative deviations are shown in Fig . 6-10 . Conversely , a computed positive value for deviation means that the point must lie above the reference tangent . A A B / A B tB / A ( a ) Positive deviation ; B located above ...
Common terms and phrases
allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bending moment bolts cantilever beam centroid column compressive stress Compute the maximum concentrated load connector cross section deformations Determine the maximum diameter elastic curve element equal equivalent Euler's formula fibers flange flexural stress flexure formula free-body diagram Hence Hooke's law horizontal Illustrative Problem kips kN·m kN/m lb.ft lb/ft length loaded as shown M₁ M₂ maximum shearing stress maximum stress method midspan mm² Mohr's circle moment of inertia neutral axis obtain P₁ plane product of inertia proportional limit R₂ R2 Figure radius reaction resisting resultant rivet segment shaft shear center shear diagram shearing force shown in Fig slope Solution span steel strain tensile stress thickness torque torsional U.S. Customary Units uniformly distributed load vertical shear weld zero ΕΙ