Strength of MaterialsSimple stress, simple strai, torsion, shear and moment in beams, beam deflections, continuous beams, combined stresses. |
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Page vii
Andrew Pytel, Ferdinand Leon Singer. APPENDIX A Moments of Inertia 519 Definition of Moment of Inertia 519 Transfer ... Product of Inertia 537 A - 8 A - 9 A - 10 A - 11 Moments of Inertia for Composite Areas 528 Product of Inertia Is Zero ...
Andrew Pytel, Ferdinand Leon Singer. APPENDIX A Moments of Inertia 519 Definition of Moment of Inertia 519 Transfer ... Product of Inertia 537 A - 8 A - 9 A - 10 A - 11 Moments of Inertia for Composite Areas 528 Product of Inertia Is Zero ...
Page 523
... moment of inertia with respect to any axis in the plane of the area is equal to the moment of inertia with respect to a parallel centroidal axis plus a transfer term composed of the product of the area multiplied by the square of the ...
... moment of inertia with respect to any axis in the plane of the area is equal to the moment of inertia with respect to a parallel centroidal axis plus a transfer term composed of the product of the area multiplied by the square of the ...
Page 538
... the centroid of the given irregular area are x and y relative to these axes . Yo 2 y xo Figure A - 16 Products of 538 A / MOMENTS OF INERTIA Product of Inertia Is Zero with Respect to Axes of Symmetry Transfer Formula for Product of ...
... the centroid of the given irregular area are x and y relative to these axes . Yo 2 y xo Figure A - 16 Products of 538 A / MOMENTS OF INERTIA Product of Inertia Is Zero with Respect to Axes of Symmetry Transfer Formula for Product of ...
Common terms and phrases
allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bending moment bolts cantilever beam centroid column compressive stress Compute the maximum concentrated load connector cross section deformations Determine the maximum diameter elastic curve element equal equivalent Euler's formula fibers flange flexural stress flexure formula free-body diagram Hence Hooke's law horizontal Illustrative Problem kips kN·m kN/m lb.ft lb/ft length loaded as shown M₁ maximum shearing stress maximum stress method midspan mm² Mohr's circle moment of inertia neutral axis obtain P₁ plane product of inertia proportional limit R₂ R2 Figure radius reaction resisting resultant rivet segment shaft shear center shear diagram shearing force shown in Fig slope Solution span steel strain tensile stress thickness torque torsional U.S. Customary Units uniformly distributed load vertical shear weld zero ΕΙ