## Strength of materials |

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Page 71

The aluminum

, is applied at the junction of the two

...

The aluminum

**segment**is 3 in. in diameter, and G,i = 4X 106 psi. The steel**segment**has a diameter of 2 in. and Ga = 12 X 106 psi. The torque, 7 = 10 kip -in., is applied at the junction of the two

**segments**. Compute the maximum shearing...

Page 95

For the time being, neglect the mass of the beam itself and consider only the

effect of the load P. Assume that a cutting plane a-a at a distance x from Rx

divides the beam into two

Fig.

For the time being, neglect the mass of the beam itself and consider only the

effect of the load P. Assume that a cutting plane a-a at a distance x from Rx

divides the beam into two

**segments**. The free-body diagram of the left**segment**inFig.

Page 108

Applying these forces to a free-body diagram of a beam

equilibrium of that

of section b-b in Fig. 4-17 are held in equilibrium by the shear and moment at

section ...

Applying these forces to a free-body diagram of a beam

**segment**producesequilibrium of that

**segment**. Thus, in Fig. 4-18, the**segments**to the left and rightof section b-b in Fig. 4-17 are held in equilibrium by the shear and moment at

section ...

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### Common terms and phrases

allowable stresses aluminum angle area-moment assumed axes axial load beam in Fig beam loaded beam shown bending bolts cantilever beam caused centroid column components compressive stress Compute the maximum concentrated load connector cross section deformations Determine the maximum diameter elastic curve element end moments equal equivalent Euler's formula factor of safety fibers Figure flange flexure formula free-body diagram Hence Hooke's law horizontal Illustrative Problem kips lb/ft length loaded as shown main plate maximum shearing stress maximum stress method midspan deflection Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius reaction rectangular resisting resultant rivet rotation segment shaft shear center shear diagram shearing force shown in Fig slope Solution span static steel strain tensile stress thickness three-moment equation torque torsional U.S. Customary Units uniformly distributed load vertical shear weld zero