Strength of MaterialsSimple stress, simple strai, torsion, shear and moment in beams, beam deflections, continuous beams, combined stresses. |
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Page 66
... torque that balances the applied torque . When this happens , slices 1 and 2 will act as a rigid unit and transmit the torque to slice 3 ; this slice will rotate enough so that the elastic fibers joining it and slice develop a resisting ...
... torque that balances the applied torque . When this happens , slices 1 and 2 will act as a rigid unit and transmit the torque to slice 3 ; this slice will rotate enough so that the elastic fibers joining it and slice develop a resisting ...
Page 78
... torque capacity of the coupling . A similar procedure may be used for three or more concentric bolt circles . As we shall see in Chapter 12 , this situation occurs in eccentrically loaded riveted or bolted connections . PROBLEMS 326. A ...
... torque capacity of the coupling . A similar procedure may be used for three or more concentric bolt circles . As we shall see in Chapter 12 , this situation occurs in eccentrically loaded riveted or bolted connections . PROBLEMS 326. A ...
Page 497
... torque required to produce it is called the limit torque and is denoted by TL . Its value can be found by setting r1 = 0 in Eq . ( 14-1 ) . This gives TL = { πr3 TYD ( b ) which is one - third more than the maximum elastic torque . For ...
... torque required to produce it is called the limit torque and is denoted by TL . Its value can be found by setting r1 = 0 in Eq . ( 14-1 ) . This gives TL = { πr3 TYD ( b ) which is one - third more than the maximum elastic torque . For ...
Common terms and phrases
allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bending moment bolts cantilever beam centroid column compressive stress Compute the maximum concentrated load connector cross section deformations Determine the maximum diameter elastic curve element equal equivalent Euler's formula fibers flange flexural stress flexure formula free-body diagram Hence Hooke's law horizontal Illustrative Problem kips kN·m kN/m lb.ft lb/ft length loaded as shown M₁ maximum shearing stress maximum stress method midspan mm² Mohr's circle moment of inertia neutral axis obtain P₁ plane product of inertia proportional limit R₂ R2 Figure radius reaction resisting resultant rivet segment shaft shear center shear diagram shearing force shown in Fig slope Solution span steel strain tensile stress thickness torque torsional U.S. Customary Units uniformly distributed load vertical shear weld zero ΕΙ