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" The angles in the same segment of a circle are equal to one another. "
The Elements of Euclid: Viz, the First Six Books, Together with the Eleventh ... - Page 81
by Euclid, Robert Simson - 1829 - 516 pages
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The Elements of Euclid, Viz: The Errors, by which Theon, Or Others, Have ...

Robert Simson - Trigonometry - 1775 - 534 pages
...the angle at the center, &c. Q^ED PROP. XXL THEO R. angles in the fame fegment of a circle are qual to one another. Let ABCD be a circle, and BAD, BED angles in the fame fegment BAED : The angles BAD, BED are equal to one another. Take F the center of the circle ABCD...
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The First Six Books: Together with the Eleventh and Twelfth

Euclid - 1781 - 552 pages
...BDC. Therefore the angle at the centre, &c. Q; ED PROP. XXI. THEO R. THE angles in the fame fegment of a circle are equal to one another. Let ABCD be a circle, and BAD, BED angK-s in the fame fegment BAED : j he angles BAD, BED are equal to one another. Take F the c.ntrc...
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Elements of Geometry;: Containing the First Six Books of Euclid, with Two ...

Euclid, John Playfair - Euclid's Elements - 1795 - 462 pages
...another. , . ' ... ' . . "•.•-. it Let ABCD be a circle, and BAD, BED angles in the fame fegment BAED : The angles BAD, BED are equal to one another. Take F the centre of the circle ABCD : And, firft, let the fegment BAED be greater than a femicircle, and join BF, FD : And becaufe the angle BFD...
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The Elements of Euclid: Viz. the First Six Books, with the Eleventh and ...

Alexander Ingram - Trigonometry - 1799 - 374 pages
...equal to one another. Let ABC D be a circle, and BAED a fegment of it; the angks in the fegment BAED are equal to one another. Take F the centre of the circle, and .A. through it draw any ftraight line AC curring BD, and join BA, AD ; and let BED be any other...
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Elements of Geometry;: Containing the First Six Books of Euclid, with a ...

John Playfair, Euclid - Circle-squaring - 1804 - 468 pages
...Therefore the angle at the centre, &.c. Q..ED PROP. XXI. THEO R. r~|~'HE angles in the fame fegment of a circle are •*- equal to one another. Let ABCD be a circle, and BAD, BED angles in the fame fegment BAED : The angles BAD, BED are equal to one another. Take F the centre of the circle ABCD...
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The Elements of Euclid: Also the Book of Euclid's Data ...cor. viz. The ...

Robert Simson - Trigonometry - 1804 - 530 pages
...center, &c. QJLD. PROP. XXI. THEOR. T HE angles in fhe fame fegment of a circle are See N. equal td one another, Let ABCD be a circle, and BAD, BED angles in the fame fegment B AED; the angles BAD, BED are equal to one another. Take F the center of the circle ABCD....
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Elements of Geometry: Containing the First Six Books of Euclid, with a ...

John Playfair - Mathematics - 1806 - 320 pages
...double of the remaining angle BAC. Therefore, the angle at the centre, &;c. QED PROP. XXI. THEOR< THE angles in the same segment of a circle are equal to...same segment BAED ; the angles BAD, BED are equal to each otherTake F, the centre of the circle ABCD. Let the segment BAED be greater than a semicircle,...
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Pantologia. A new (cabinet) cyclopædia, by J.M. Good, O. Gregory ..., Volume 5

John Mason Good - 1813 - 714 pages
...circumference, upon the same ha.-e, that is, upon the same part of the circumference. Prop, XXI. Theor. The angles in the same segment of a circle are equal to one another. Prop. XXI I. Theor. The opposite angles of any quadrilateial figure described in a circle, are together...
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A Treatise on Surveying, Containing the Theory and Practice: To which is ...

John Gummere - Surveying - 1814 - 398 pages
...same part of the circumference : thus the angle EEC is double of the angle BAG. Fig- 38. i • 11. The angles in the same segment of a circle are equal to one another : thus the angle BAD is equal to the angle BED ; also the angle BCD is equal to the angle BFD. Fig....
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The Elements of Euclid: Viz. the First Six Books, Together with the Eleventh ...

Euclides - 1816 - 588 pages
...the angle at the centre, &c. PROP. XXI. THEOR. THE angles in the same segment of a circle are See N. equal to one another. Let ABCD be a circle, and BAD,...: And, first, let the segment BAED be greater than a semicircle, , and join BF, FD: And because the " angle BFD is at the centre, and the angle BAD at...
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