## Introduction to Mechanics of Deformable Solids |

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Page 53

Longitudinal ( diametral ) planes through the axis of the tube also will have a

shear stress T

be equality of cross shears on planes at right angles . Reasoning similar to that ...

Longitudinal ( diametral ) planes through the axis of the tube also will have a

shear stress T

**acting**on them ( Figs . 4 . 6 and 4 . 7 ) , because there must alwaysbe equality of cross shears on planes at right angles . Reasoning similar to that ...

Page 228

The principal stress of 5000 psi compression

whose coordinates are ( - 5000 , 0 ) . The line joining points 1 and 3 is a diameter

of the Mohr ' s circle for the components of stress

The principal stress of 5000 psi compression

**acting**on plane 3 plots as point 3whose coordinates are ( - 5000 , 0 ) . The line joining points 1 and 3 is a diameter

of the Mohr ' s circle for the components of stress

**acting**on any plane ...Page 319

lb

month and at the same time the angular rotation rate is 1 . 5° per month . D . Find

the rate of extension and the rate of rotation when both R = 40 , 000 lb and T = 80

...

lb

**acting**alone . C . Find R and T when the rate of extension is 0 . 06 in . permonth and at the same time the angular rotation rate is 1 . 5° per month . D . Find

the rate of extension and the rate of rotation when both R = 40 , 000 lb and T = 80

...

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acting actual addition angle answer applied approximation assemblage axial force axis beam behavior bending circle circular column combined compatibility components compression compressive stress Consider constant creep cross section curve deflection deformation determined direction displacement effect elastic equal equation equations of equilibrium example Find force given gives homogeneous idealization increase initial interior isotropic length limit linear linear-elastic load material maximum Maxwell modulus moment nonlinear normal obtained plane plastic positive pressure principal Prob problem produced pure radius range ratio relation replaced requires response result rotation shear stress shell shown shows simple sketch solution solved statically steel strain stress-strain relations structural substitution Suppose surface symmetry temperature tensile tension tion tube twisting uniform virtual viscous yield zero