## Introduction to Mechanics of Deformable Solids |

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Page 61

Three - dimensional sketches and the conventional two - dimensional

representations are drawn side by side to reemphasize that lines on the

conventional drawing represent planes perpendicular to the paper and that the

shear stresses

Three - dimensional sketches and the conventional two - dimensional

representations are drawn side by side to reemphasize that lines on the

conventional drawing represent planes perpendicular to the paper and that the

shear stresses

**act**...Page 233

The direction of 01 and the plane on which it

approximately by inspection . As illustrated by the square element of Fig . 11 .

15a , if oz > Oy , the direction of o1 in the absence of would be the direction of the

heavy arrow ...

The direction of 01 and the plane on which it

**acts**can be determinedapproximately by inspection . As illustrated by the square element of Fig . 11 .

15a , if oz > Oy , the direction of o1 in the absence of would be the direction of the

heavy arrow ...

Page 236

18 Principal stresses exist and

11 . 1 ) . as B changes . These " principal stresses " oy , 0 , are not real principal

stresses . As shown in Fig . 11 . 176 , og and o ,

18 Principal stresses exist and

**act**on planes of zero shear stress ( see also Fig .11 . 1 ) . as B changes . These " principal stresses " oy , 0 , are not real principal

stresses . As shown in Fig . 11 . 176 , og and o ,

**act**on planes which in general ...### What people are saying - Write a review

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acting actual addition angle answer applied approximation assemblage axial force axis beam behavior bending circle circular column combined compatibility components compression compressive stress Consider constant creep cross section curve deflection deformation determined direction displacement effect elastic equal equation equations of equilibrium example Find force given gives homogeneous idealization increase initial interior isotropic length limit linear linear-elastic load material maximum Maxwell modulus moment nonlinear normal obtained plane plastic positive pressure principal Prob problem produced pure radius range ratio relation replaced requires response result rotation shear stress shell shown shows simple sketch solution solved statically steel strain stress-strain relations structural substitution Suppose surface symmetry temperature tensile tension tion tube twisting uniform virtual viscous yield zero