## Introduction to Mechanics of Deformable Solids |

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Page 77

to zero ( Fig . 5 . 4 ) and results in a uniaxial compression po = 0 in the radial

direction . This uniaxial compression o is equivalent to ( produces the same

creep ...

**Addition**of this hydrostatic pressure reduces the biaxial tensile stress in the shellto zero ( Fig . 5 . 4 ) and results in a uniaxial compression po = 0 in the radial

direction . This uniaxial compression o is equivalent to ( produces the same

creep ...

Page 296

Daniel Charles Drucker. the presconents and é Note that in Eq . ( 13 . 2 : 4 ) the

presence of the shear - stress component Tae in

components oa , Oc increases J , and therefore for n > 1 increases the magnitude

...

Daniel Charles Drucker. the presconents and é Note that in Eq . ( 13 . 2 : 4 ) the

presence of the shear - stress component Tae in

**addition**to the normal - stresscomponents oa , Oc increases J , and therefore for n > 1 increases the magnitude

...

Page 317

A change of Ek in the oa of the Mises solution does not violate either requirement

. Therefore at each position r in the cylinder ,

of o , up to a maximum of k will not change the state from one of plane strain .

A change of Ek in the oa of the Mises solution does not violate either requirement

. Therefore at each position r in the cylinder ,

**addition**or subtraction of any valueof o , up to a maximum of k will not change the state from one of plane strain .

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acting actual addition angle answer applied approximation assemblage axial force axis beam behavior bending circle circular column combined compatibility components compression compressive stress Consider constant creep cross section curve deflection deformation determined direction displacement effect elastic equal equation equations of equilibrium example Find force given gives homogeneous idealization increase initial interior isotropic length limit linear linear-elastic load material maximum Maxwell modulus moment nonlinear normal obtained plane plastic positive pressure principal Prob problem produced pure radius range ratio relation replaced requires response result rotation shear stress shell shown shows simple sketch solution solved statically steel strain stress-strain relations structural substitution Suppose surface symmetry temperature tensile tension tion tube twisting uniform virtual viscous yield zero