## Introduction to Mechanics of Deformable Solids |

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Page 72

Of course , the stresses computed from the dead weights alone are not the actual

stresses . A normal

the material . As seen in Fig . 5 . 1 , the standard tension test then starts out as ...

Of course , the stresses computed from the dead weights alone are not the actual

stresses . A normal

**compressive stress**po must be added on every plane throughthe material . As seen in Fig . 5 . 1 , the standard tension test then starts out as ...

Page 154

A . When the extreme fiber stress ( the maximum stress ) just reaches oo , find the

moments 1 . MY 2 . M , Y about the ... Determine the ratio of the maximum tensile

stress to the maximum

A . When the extreme fiber stress ( the maximum stress ) just reaches oo , find the

moments 1 . MY 2 . M , Y about the ... Determine the ratio of the maximum tensile

stress to the maximum

**compressive stress**under pure bending . 3 . Find the ...Page 233

16 Plane stress - zero cannot be ignored . The direction ... ( d ) to emphasize that

now the maximum

are compressive , the algebraically smaller principal stress must be compressive

.

16 Plane stress - zero cannot be ignored . The direction ... ( d ) to emphasize that

now the maximum

**compressive stress**is sought . When either oz or Oy or bothare compressive , the algebraically smaller principal stress must be compressive

.

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acting actual addition angle answer applied approximation assemblage axial force axis beam behavior bending circle circular column combined compatibility components compression compressive stress Consider constant creep cross section curve deflection deformation determined direction displacement effect elastic equal equation equations of equilibrium example Find force given gives homogeneous idealization increase initial interior isotropic length limit linear linear-elastic load material maximum Maxwell modulus moment nonlinear normal obtained plane plastic positive pressure principal Prob problem produced pure radius range ratio relation replaced requires response result rotation shear stress shell shown shows simple sketch solution solved statically steel strain stress-strain relations structural substitution Suppose surface symmetry temperature tensile tension tion tube twisting uniform virtual viscous yield zero