## Introduction to Mechanics of Deformable Solids |

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Page 233

The

approximately by inspection . As illustrated by the square element of Fig . 11 .

15a , if oz > Oy , the

heavy arrow ...

The

**direction**of 01 and the plane on which it acts can be determinedapproximately by inspection . As illustrated by the square element of Fig . 11 .

15a , if oz > Oy , the

**direction**of o1 in the absence of would be the**direction**of theheavy arrow ...

Page 248

Daniel Charles Drucker. Normal , or direct , strain e in any

in length per unit of length in that

decrease in angle between the positive

Figs .

Daniel Charles Drucker. Normal , or direct , strain e in any

**direction**is the changein length per unit of length in that

**direction**( Fig . 1 . 5 ) . Shear strain y is thedecrease in angle between the positive

**directions**of two perpendicular lines (Figs .

Page 370

23 , the shear stresses Tty and Tız are in the

The magnitude of the shear flow ... The

material behavior but certainly cannot be vertical . Therefore the

cannot ...

23 , the shear stresses Tty and Tız are in the

**directions**indicated by the arrows .The magnitude of the shear flow ... The

**direction**of V , V = P , will vary withmaterial behavior but certainly cannot be vertical . Therefore the

**direction**of Pcannot ...

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acting actual addition angle answer applied approximation assemblage axial force axis beam behavior bending circle circular column combined compatibility components compression compressive stress Consider constant creep cross section curve deflection deformation determined direction displacement effect elastic equal equation equations of equilibrium example Find force given gives homogeneous idealization increase initial interior isotropic length limit linear linear-elastic load material maximum Maxwell modulus moment nonlinear normal obtained plane plastic positive pressure principal Prob problem produced pure radius range ratio relation replaced requires response result rotation shear stress shell shown shows simple sketch solution solved statically steel strain stress-strain relations structural substitution Suppose surface symmetry temperature tensile tension tion tube twisting uniform virtual viscous yield zero