Introduction to Mechanics of Deformable Solids |
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Page 120
... equal bars . M2 + M3 " = 0 de 1 do dt = Sketch drawn for n large in + ( - ) " + Em dt of 2 times the stress in the ... equal and opposite character M2 = -M3 ' ( Fig . 7.10 ) . Remember that it is not the residual stresses σ2 " and σ3 ...
... equal bars . M2 + M3 " = 0 de 1 do dt = Sketch drawn for n large in + ( - ) " + Em dt of 2 times the stress in the ... equal and opposite character M2 = -M3 ' ( Fig . 7.10 ) . Remember that it is not the residual stresses σ2 " and σ3 ...
Page 187
... equal thickness . From ( 9.1 : 39 ) : P21 = 212 b σο + Po From ( 9.1 : 37 ) : b2 2t2b b2 P12 = = P21 το + po a2 a2 a2 From ( 9.1 : 38 ) : ( 9.1 : 40 ) ( 9.1 : 41 ) L Pal = a 201 σo + P12 σο = ( 21 , +212 1 + 21 , + po 2123 b2 a2 b2 a2 ...
... equal thickness . From ( 9.1 : 39 ) : P21 = 212 b σο + Po From ( 9.1 : 37 ) : b2 2t2b b2 P12 = = P21 το + po a2 a2 a2 From ( 9.1 : 38 ) : ( 9.1 : 40 ) ( 9.1 : 41 ) L Pal = a 201 σo + P12 σο = ( 21 , +212 1 + 21 , + po 2123 b2 a2 b2 a2 ...
Page 380
... Equal and opposite tensile forces P act on the disk . In the motion from H to H " , the imagined disk must stretch by u * sin 2a . No other internal work is done , and the tensile forces obviously do positive work because of the ...
... Equal and opposite tensile forces P act on the disk . In the motion from H to H " , the imagined disk must stretch by u * sin 2a . No other internal work is done , and the tensile forces obviously do positive work because of the ...
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actual addition angle answer applied assemblage axes axial axis beam behavior bending circle circular column compatibility components compression compressive stress Consider constant creep cross section curve cylinder deflection deformation determined diameter direction displacement effect elastic equal equation equilibrium example Figure Find force given gives homogeneous idealization increase initial interior isotropic length limit linear linear-elastic load material maximum Maxwell modulus moment needed nonlinear normal obtained outer plane plastic positive pressure principal Prob problem produced pure radius range ratio replaced requires response result rotation shaft shear stress shell shown shows simple sketch solid solution steel strain stress-strain relations structural Suppose surface symmetry temperature tensile tension thickness thin-walled torsion tube twisting uniform unloading viscous yield zero