Introduction to Mechanics of Deformable Solids |
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Page 98
... equation for linear - elastic bars , the deformation condition expressed in terms of force , is PL + α7L700 + A7E7 P8L8 ASES + α8L80c P , L , A , E , + α9L90c = 0 when the supports do not move . This equation plus two independent equa ...
... equation for linear - elastic bars , the deformation condition expressed in terms of force , is PL + α7L700 + A7E7 P8L8 ASES + α8L80c P , L , A , E , + α9L90c = 0 when the supports do not move . This equation plus two independent equa ...
Page 180
... equation ( 9.1 : 16 ) gives d στ σ , - 2100 = [ ( 1 2νσο ― dr v ) roe - vro , ] - ( 9.1 : 18 ) on the assumption that E does not vary with r . Take the material as homoge- neous throughout so that is constant also , and use the equation ...
... equation ( 9.1 : 16 ) gives d στ σ , - 2100 = [ ( 1 2νσο ― dr v ) roe - vro , ] - ( 9.1 : 18 ) on the assumption that E does not vary with r . Take the material as homoge- neous throughout so that is constant also , and use the equation ...
Page 243
... equation of Eqs . ( 11.4 : 13 ) . The next equation is obtained with i = = 3 . 2 and the last with i Equations ( 11.4 : 21 ) can be rewritten with d ;, the Kronecker delta ( 11.1 : 6 ) , ni = njdji ( σji — σpdji ) N ; = 0 - Therefore ...
... equation of Eqs . ( 11.4 : 13 ) . The next equation is obtained with i = = 3 . 2 and the last with i Equations ( 11.4 : 21 ) can be rewritten with d ;, the Kronecker delta ( 11.1 : 6 ) , ni = njdji ( σji — σpdji ) N ; = 0 - Therefore ...
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actual addition angle answer applied assemblage axes axial axis beam behavior bending circle circular column compatibility components compression compressive stress Consider constant creep cross section curve cylinder deflection deformation determined diameter direction displacement effect elastic equal equation equilibrium example Figure Find force given gives homogeneous idealization increase initial interior isotropic length limit linear linear-elastic load material maximum Maxwell modulus moment needed nonlinear normal obtained outer plane plastic positive pressure principal Prob problem produced pure radius range ratio replaced requires response result rotation shaft shear stress shell shown shows simple sketch solid solution steel strain stress-strain relations structural Suppose surface symmetry temperature tensile tension thickness thin-walled torsion tube twisting uniform unloading viscous yield zero