## Electromagnetic fieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |

### From inside the book

Results 1-3 of 80

Page 73

and therefore where *,(/•)- T% (4-14) 4wt(/ Qm=[ p^W (4-15) and where V{r) is the

volume of the sphere of radius r. There are two cases to consider. 1. Outside ...

**becomes**, with the use of (1-92): <f)Eda = (f) Er(r)Tida= E,(r)<£da=4irr2E,(r) (4-13)and therefore where *,(/•)- T% (4-14) 4wt(/ Qm=[ p^W (4-15) and where V{r) is the

volume of the sphere of radius r. There are two cases to consider. 1. Outside ...

Page 83

As before, R2 = z2 + r'2 — 2zr' cos 9', so that (5-7)

2zr'cos0')1/2 where we have used ... over dtp' can be performed at once and

gives In. If we again let /i = cos0', and use (2-22), we find that (5-17)

As before, R2 = z2 + r'2 — 2zr' cos 9', so that (5-7)

**becomes**4,rco-'o Jo h (z2 + r'2-2zr'cos0')1/2 where we have used ... over dtp' can be performed at once and

gives In. If we again let /i = cos0', and use (2-22), we find that (5-17)

**becomes**...Page 360

... is lioMa3 r2* (□□" sin3 O'dO'dy 47T J0 Jo (z* + a2- 2zacos0') 3/2 (20-19) The

integration over <jp' gives a value of 2-rr; if we use sin20'= 1 -cos20', and change

the variable of integration by means of (2-22), we find that this

... is lioMa3 r2* (□□" sin3 O'dO'dy 47T J0 Jo (z* + a2- 2zacos0') 3/2 (20-19) The

integration over <jp' gives a value of 2-rr; if we use sin20'= 1 -cos20', and change

the variable of integration by means of (2-22), we find that this

**becomes**li^Ma3 ...### What people are saying - Write a review

We haven't found any reviews in the usual places.

### Other editions - View all

### Common terms and phrases

angle assume axis becomes bound charge boundary conditions bounding surface calculate capacitance charge density charge distribution charge q circuit conductor consider const constant corresponding Coulomb's law cross section current density current element curve cylinder defined dielectric direction displacement distance electric field electromagnetic electrostatic energy equal equipotential evaluate example Exercise expression field point flux force free charge free currents frequency function given illustrated in Figure induction infinitely long integral integrand Laplace's equation line charge located Lorentz Lorentz transformation magnitude material Maxwell's equations molecule normal components obtained origin particle perpendicular plane wave point charge polarized position vector potential difference propagation properties quadrupole quantities radiation region relation result satisfy scalar potential shown in Figure situation solenoid spherical substitute surface current surface integral tangential components total charge unit vacuum vector potential velocity volume write written xy plane zero