Electromagnetic FieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |
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Page 22
... corresponding differentials . Since we always treat these differentials as positive as written , the actual component will be obtained by multiplying this product by a plus or a minus sign depending on the sign of the corresponding ...
... corresponding differentials . Since we always treat these differentials as positive as written , the actual component will be obtained by multiplying this product by a plus or a minus sign depending on the sign of the corresponding ...
Page 483
... corresponding expression for tan20 ; in order that ( E , / E , ) = 0 . ( c ) Now assume that medium 1 is a vacuum and show that a polarizing angle is possible for the parallel case only when Ke2 > Km2 . ( d ) Find the corresponding ...
... corresponding expression for tan20 ; in order that ( E , / E , ) = 0 . ( c ) Now assume that medium 1 is a vacuum and show that a polarizing angle is possible for the parallel case only when Ke2 > Km2 . ( d ) Find the corresponding ...
Page 572
... corresponding potentials in S are φ = γφ ' = Yq 4π € o [ y2 ( x − vt ) 2 + y2 + z2 ] 1 / 2 βγφ ' Μεγαν A = A ̧Î = с 4π [ y2 ( x − vt ) 2 + y2 + z2 +22 ] 1/2 since A , A , = 0 . = ( 28-153 ) ( 28-154 ) If we look at the special case ...
... corresponding potentials in S are φ = γφ ' = Yq 4π € o [ y2 ( x − vt ) 2 + y2 + z2 ] 1 / 2 βγφ ' Μεγαν A = A ̧Î = с 4π [ y2 ( x − vt ) 2 + y2 + z2 +22 ] 1/2 since A , A , = 0 . = ( 28-153 ) ( 28-154 ) If we look at the special case ...
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Common terms and phrases
Ampère's law angle assume axis becomes bound charge boundary conditions bounding surface calculate capacitance capacitor charge density charge distribution charge q circuit conductor consider constant coordinates corresponding Coulomb's law current density curve cylinder defined dielectric dipole direction displacement distance E₁ electric field electromagnetic electrostatic energy equal evaluate example Exercise expression field point flux force free charge free currents frequency function given induction infinitely long integral integrand k₂ Laplace's equation located Lorentz transformation magnetic magnitude material Maxwell's equations normal components obtained origin parallel particle perpendicular plane wave plates point charge polarized position vector potential difference quadrupole quantities radiation radius rectangular region result satisfy scalar scalar potential shown in Figure solenoid sphere spherical tangential components unit vacuum vector potential velocity volume write written xy plane zero Απερ дх Мо