## Electromagnetic fieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |

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Page 188

The total interaction energy will then be obtained by integrating (10-92) over the

volume, we can take it out of the integral and use (10-2) to get Urnt= — p-E„t in ...

The total interaction energy will then be obtained by integrating (10-92) over the

**dielectric**to give ^-/P-L* (10-93) For example, if Eext does not vary much over thevolume, we can take it out of the integral and use (10-2) to get Urnt= — p-E„t in ...

Page 189

Force on a

capacitor with square plates of side L so that A — L2. We also assume we have a

solid slab of

edge ...

Force on a

**dielectric**. In order to be specific, we consider a parallel platecapacitor with square plates of side L so that A — L2. We also assume we have a

solid slab of

**dielectric**of the correct size to just fit between the plates. We neglectedge ...

Page 193

i. h.

halves by a plane that passes through the common center of the spherical

conductors. Show that the capacitance is given by C = 2ir(€l+€^)ab/(b — a). 10-

29 The ...

i. h.

**dielectrics**with permittivities shown. The total volume is divided exactly intohalves by a plane that passes through the common center of the spherical

conductors. Show that the capacitance is given by C = 2ir(€l+€^)ab/(b — a). 10-

29 The ...

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angle assume axis becomes bound charge boundary conditions bounding surface calculate capacitance charge density charge distribution charge q circuit conductor consider const constant corresponding Coulomb's law cross section current density current element curve cylinder defined dielectric direction displacement distance electric field electromagnetic electrostatic energy equal equipotential evaluate example Exercise expression field point flux force free charge free currents frequency function given illustrated in Figure induction infinitely long integral integrand Laplace's equation line charge located Lorentz Lorentz transformation magnitude material Maxwell's equations molecule normal components obtained origin particle perpendicular plane wave point charge polarized position vector potential difference propagation properties quadrupole quantities radiation region relation result satisfy scalar potential shown in Figure situation solenoid spherical substitute surface current surface integral tangential components total charge unit vacuum vector potential velocity volume write written xy plane zero