Electromagnetic FieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |
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Page 122
... force to be outward from the conductor . In other words , we are led once more to ( 7-50 ) that gives the electrostatic force per unit area as always a tension , that is , in the direction of the outward normal ân . If the internal ...
... force to be outward from the conductor . In other words , we are led once more to ( 7-50 ) that gives the electrostatic force per unit area as always a tension , that is , in the direction of the outward normal ân . If the internal ...
Page 189
... force on the dielectric ; the total displacement of the dielectric is L , so that using ( 7-37 ) we get < F > == = L -AU - ( ~ - ~ - ~ -1 ) 21/0 Uo L ( 10-97 ) which is positive , showing that ... force Feo when there is vacuum FORCES 189.
... force on the dielectric ; the total displacement of the dielectric is L , so that using ( 7-37 ) we get < F > == = L -AU - ( ~ - ~ - ~ -1 ) 21/0 Uo L ( 10-97 ) which is positive , showing that ... force Feo when there is vacuum FORCES 189.
Page 245
... forces on a magnetic compass needle . Ampère heard of Oersted's result and quickly found that an electric current could also exert a force on another electric current . He began a systematic study of these forces , and , by means of a ...
... forces on a magnetic compass needle . Ampère heard of Oersted's result and quickly found that an electric current could also exert a force on another electric current . He began a systematic study of these forces , and , by means of a ...
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Ampère's law angle assume axis becomes bound charge boundary conditions bounding surface calculate capacitance capacitor charge density charge distribution charge q circuit conductor consider constant coordinates corresponding Coulomb's law current density curve cylinder defined dielectric dipole direction displacement distance E₁ electric field electromagnetic electrostatic energy equal evaluate example Exercise expression field point flux force free charge free currents frequency function given induction infinitely long integral integrand k₂ Laplace's equation located Lorentz transformation magnetic magnitude material Maxwell's equations normal components obtained origin parallel particle perpendicular plane wave plates point charge polarized position vector potential difference quadrupole quantities radiation radius rectangular region result satisfy scalar scalar potential shown in Figure solenoid sphere spherical tangential components unit vacuum vector potential velocity volume write written xy plane zero Απερ дх Мо