Electromagnetic FieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |
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Page 458
... medium 1 to medium 2 according to our standard conven- tion . B The total electric field at a given point in medium 1 will be E1 = E¡ + E ,, while that in 2 is E2 = E ,. Now at any point on the boundary where r = r , we must have E ...
... medium 1 to medium 2 according to our standard conven- tion . B The total electric field at a given point in medium 1 will be E1 = E¡ + E ,, while that in 2 is E2 = E ,. Now at any point on the boundary where r = r , we must have E ...
Page 483
... medium of index of refraction 4.5 . The second medium is a nonmagnetic glass of index 1.5 . The incident wave is linearly polarized such that the components of Eo , perpendicular and parallel to the plane of incidence are equal . Find 6 ...
... medium of index of refraction 4.5 . The second medium is a nonmagnetic glass of index 1.5 . The incident wave is linearly polarized such that the components of Eo , perpendicular and parallel to the plane of incidence are equal . Find 6 ...
Page 484
... medium . For the remainder of this exercise , assume a perfect conductor ( σ2 → ∞ ) . Assume Eo to be real for simplicity , and find E , real , that is , the total physical electric field in the incident medium and show that it is a ...
... medium . For the remainder of this exercise , assume a perfect conductor ( σ2 → ∞ ) . Assume Eo to be real for simplicity , and find E , real , that is , the total physical electric field in the incident medium and show that it is a ...
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Ampère's law angle assume axis becomes bound charge boundary conditions bounding surface calculate capacitance capacitor charge density charge distribution charge q circuit conductor consider constant coordinates corresponding Coulomb's law current density curve cylinder defined dielectric dipole direction displacement distance E₁ electric field electromagnetic electrostatic energy equal evaluate example Exercise expression field point flux force free charge free currents frequency function given induction infinitely long integral integrand k₂ Laplace's equation located Lorentz transformation magnetic magnitude material Maxwell's equations normal components obtained origin parallel particle perpendicular plane wave plates point charge polarized position vector potential difference quadrupole quantities radiation radius rectangular region result satisfy scalar scalar potential shown in Figure solenoid sphere spherical tangential components unit vacuum vector potential velocity volume write written xy plane zero Απερ дх Мо